The movement of glucose into the cell, against its concentration gradient, can be powered by the...
The movement of glucose into the cell, against its concentration gradient, can be powered by the co-transport of Na+ into the cell. Explain this movement with respect to the net entropy of the system (i.e. thermodynamics).
Homework Answers
Answer: This question i have to write pointswise,because it'e asy to understand you....
- There are two factors at play here.
- One is the thermodynamic. deltaG which is based on concentration gradients.
- The value for this is positive because you are going against the concentration.
- The other factor is electrostatic. z*F*deltaPsi
- The value for this is more negative than the above positive value. This is because the net charge inside the cell is negative, thus it is favorable to bring an overall net positive charge (Na+ is positive and Glc is neutral) inside.
- The favorability of going with the electrostatic gradient (moving a positive charge Na+, from a highly positive place to a highly negative place) is much more favorable than moving it against its concentration gradient.
-
Thus the net is a negative deltaG which means transport is favorable.
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The movement of glucose into the cell, against its concentration
gradient, can be powered by the...
moving a large molecule such as glucose against its own concentration gradient and in the opposite...
moving a large molecule such as glucose against its own
concentration gradient and in the opposite direction of passive
diffusion of NA+ is
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The Na –glucose symport system of intestinal epithelial cells couples the \"downhill\" transport of two Na...
The Na –glucose symport system of
intestinal epithelial cells couples the \"downhill\" transport of
two Na ions into the cell to the \"uphill\" transport of glucose,
pumping glucose into the cell against its concentration gradient.
If the Na concentration outside the cell ([Na ]out) is 155 mM and
that inside the cell ([Na ]in) is 17.0 mM, and the cell potential
is -53.0 mV (inside negative), calculate the maximum ratio of
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Moving a large molecule such as glucose against its own concentration gradient and in the opposite direction of passive diffusion of Natis: Co-Transport B. Facilitated Diffusion c Primary Active Transport Counter-Transport
5/2400 Resources Give Up Hint Intestinal epithelial cells pump glucose into the cell against its concentration gradient using the Nat-glucose symporter. Recall that the Nat concentration is significantly higher outside the cell than inside the cell. The symporter couples the "downhill" transport of two Nations into the cell to the "uphill" transport of glucose into the cell. If the Na+ concentration outside the cell (INa1.) is 151 mM and that inside the cell ([Na]) is 23.0 mm, and the cell...
The Na –glucose symport system of
intestinal epithelial cells couples the \"downhill\" transport of
two Na ions into the cell to the \"uphill\" transport of glucose,
pumping glucose into the cell against its concentration gradient.
If the Na concentration outside the cell ([Na ]out) is 155 mM and
that inside the cell ([Na ]in) is 17.0 mM, and the cell potential
is -53.0 mV (inside negative), calculate the maximum ratio of
[glucose]in to [glucose]out that could theoretically be produced if...
The Na –glucose symport system of intestinal epithelial cells
couples the "downhill" transport of two Na ions into the cell to
the "uphill" transport of glucose, pumping glucose into the cell
against its concentration gradient. If the Na concentration outside
the cell ([Na+]out) is 163 mM and that inside
the cell ([Na+]in) is 17.0 mM, and the cell
potential is -53.0 mV (inside negative), calculate the maximum
ratio of [glucose]in to [glucose]out that
could theoretically be produced if the energy...
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