If there are are 9 individuals in population "X", and with regards to gene "A", 4...
If there are are 9 individuals in population "X", and with regards to gene "A", 4 individuals are AA, 3 are Aa and 2 are aa, what is the frequency of the recessive allele?
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.456
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.388
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.611
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The numerical value cannot be determined given that this population is too small and is not in Hardy-Weinberg equilibrium.
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Willie Nelson and Metallica invented population genetics!!
I know is B but I do not know how to get there. Please explain steps
Homework Answers
4 individuals have AA genotype. So the frequency of allele A for 4 individuals = 2×4 = 8 ( multiplied by 2 because there are two AA alleles). But there are more 3 allele in individuals with allele "Aa". So total frequency of A = 8+3 = 11.
Similarly frequency of recessive allele "a" = 3 + (2×2) = 7
So total frequency (A + a) = 11+7 = 18.
Now frequency of recessive allele (a) = 7/18 = 0.388
So this is how we can calculate frequency of a given allele
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If there are are 9 individuals in population "X", and with
regards to gene "A", 4...
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