In a population that meets Hardy- Weinberg equilibrium assumptions, 81% of the individuals are homozygous for...
In a population that meets Hardy- Weinberg equilibrium assumptions, 81% of the individuals are homozygous for the recessive allele. What percentage of the individuals would be expected to be heterozygous for this locus in the next generation?
Homework Answers
The population has 81% of the individuals homozygous for the recessive allele.
q2 = 0.81
Therefore, q = 0.9
p = 0.1
The percentage of the individuals expected to be heterozygous in the next generation = 2pq
= 2(0.1)(0.9) = 0.18 or 18%
Thus, the answer is 18%.
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