Individual homozygous dominant for a population at 16 percent recessive would make up
p^{2} + 2pq + q^{2} = 1
p + q = 1
0.16 + q = 1
q = 1- 0.16
= 0.84 i.e 84 % (dominant)
2 p x q
2 x 0.16 x 0.84 = 0.2688 i.e ( c ) 24% approx
3. Diamptomous priminas frequency with short antenna:
(0.09) (a)
If individuals homozygous for a recessive mutation make up 16% of a population at Hardy-Weinberg equilibrium,...
In a population that is in Hardy Weinberg equilibrium, 49% of the individuals are recessive homozygotes for a certain trait. In a population of 5500, calculate the following: a) The number of homozygous recessive individuals in the population b) The number of heterozygotes in the population
Consider a randomly-mating population that is not evolving. If the population consists of 16% homozygous recessive individuals, what percentage of the population is heterozygous? A. 84% B. 50% C. 42% D. 48%
Use the Hardy-Weinberg equations (p2 + 2pq + q2 = 1 and p + q = 1) to find the genotypes of the following hypothetical phenotypic information: a. Within a particular population, you observe that 450 individuals have freckles (dominant, F) and 550 do not have freckles (recessive, f). b. Homozygous dominant (frequency) ______(A)_________ c. Heterozygous (frequency) ______(B)_____________ d. Homozygous recessive (frequency) _______(C)____________
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2. Hardy-Weinberg Equilibrium; chi-square test Sickle cell anemia is a recessive disorder caused by a recessive mutation (S) in the b-hemoglobin gene. 80% of affected SS individuals die before reproducing. Heterozygotes (AS) and homozygous dominant (AA) individuals do not have sickle cell anemia. The table below shows the number of people of each genotype in a population of 100 people in population of Cameroon. Observed # individuals in a Cameroon population AA AS SS 62 32 6 What are the...
Question 7 4 pts A trait (or, phenotype) due to homozygous recessive mutation in a large randomly mating population affects 1 in 1,000 diploid individuals. What is the allele frequency for this recessive allele, assuming the population is in Hardy-Weinberg equilibrium? O 0.001 O 0.031 O 0.1 0 1
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2. Assume a population is in Hardy-Weinberg equilibrium for a given genetic autosomal trait. What proportion of individuals in the population are heterozygous for the gene if the frequency of the recessive allele is 1%.
Evolution 1. Assume this population is in Hardy-Weinberg equilibrium. In a population of 120 cats, 35 are black. Black cats have the bb genotype. Find the allelic frequency of the dominant and recessive allele. 2. Assume this population is in Hardy-Weinberg equilibrium. A litter of 10 puppies has both tipped ears (a) and floppy ears (A). If 4 puppies have tipped ears in the litter. What is the frequency of the recessive allele? 3. Assume this population is in Hardy-Weinberg...
Cystic fibrosis is an autosomal recessive disorder. In one population, the frequency of affected individuals (A 2 A 2) is 0.0004 Assuming that this population is under Hardy- Weinberg equilibrium, calculate all allele frequencies and genotype frequencies. Enter your numerical answers in the boxes below. Express each answer to four decimal places. Frequency of A1: Frequency of A2: Frequency of homozygous dominant: Frequency of homozygous recessive: Frequency of heterozygous