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Individual homozygous dominant for a population at 16 percent recessive would make up
p2 + 2pq + q2 = 1
p + q = 1
0.16 + q = 1
q = 1- 0.16
= 0.84 i.e 84 % (dominant)
2 p x q
2 x 0.16 x 0.84 = 0.2688 i.e ( c ) 24% approx
3. Diamptomous priminas frequency with short antenna:
If individuals homozygous for a recessive mutation make up 16% of a population at Hardy-Weinberg equilibrium,...
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