Question

Enzyme X has a Km for substrate A which is twice as large as its Km...

Enzyme X has a Km for substrate A which is twice as large as its Km for substrate B. If the enzyme is added to a solution containing equal, but low concentrations of A and B and Vmax for A and B are equal:

substrate A will be used at a rate equal to substrate B

substrate A will be used at a rate greater than substrate

substrate B will be used at a rate greater than substrate A.

substrate A will be used exclusively.

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Answer #1

Km is the substrate concentration when the rate of reaction (Vo) is equal to half of the Vmax, lower Km means the at lower concentrations of the substrate the rate of reaction is high, here Km of B=Km of A/2, that is Km of B less than the Km of A and Vmax of both reactions are same so at lower concentrations substrate B will be used at a greater rate than substrate A. so the answer is substrate B will be used at a rate greater than substrate A.

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