2. If 10.00 g of magnesium is reacted with 95.75 g of copper (II) sulphate, magnesium sulphate and copper are formed. a. Which reactant is in excess? b. Calculate the mass of copper formed.
2. If 10.00 g of magnesium is reacted with 95.75 g of copper (II) sulphate, magnesium...
In lab, you reacted copper metal with aqueous nitric acid to produce aqueous copper (II) nitrate, nitrogen dioxide gas and water. Cu (s) + 4HNO3 (aq) ---- > Cu(NO3)2 (aq) + 2NO2 (g) + 2H2O (l) a) If 0.210 gram of copper is reacted with 35.0 mL of 0.551 mol/L nitric acid, how many molecules and how grams of copper (II) nitrate are produced? b) How many moles of the reagent that is in excess are left over? c) If...
In lab, you reacted copper metal with aqueous nitric acid to produce aqueous copper (II) nitrate, nitrogen dioxide gas and water. Cu (s) + 4HNO3 (aq) ---- > Cu(NO3)2 (aq) + 2NO2 (g) + 2H2O (l) a) If 0.210 gram of copper is reacted with 35.0 mL of 0.551 mol/L nitric acid, how many molecules and how grams of copper (II) nitrate are produced? b) How many moles of the reagent that is in excess are left over? c) If...
Assuming an efficiency of 39.50%, calculate the actual yield of magnesium nitrate formed from 110.0 g of magnesium and excess copper(II) nitrate. Mg+Cu(NO3)2⟶Mg(NO3)2+Cu actual yield: g
Assuming an efficiency of 46.40%, calculate the actual yield of magnesium nitrate formed from 125.3 g of magnesium and excess copper(II) nitrate. Mg+Cu(NO3)2⟶Mg(NO3)2+Cu actual yield:
I need number five please Mole Ratios Copper(II) chloride (CuCl,; 0.98 g) was dissolved in water and a piece of aluminum wire (Al: 056 p) was placed in the sbittion. The blue color due to copper(II) chloride soon faded and a red precipitate of solid copper was observed. After the blue color had disappeared completely, the leftover aluminum wire was removed from the solution and weighed. The mass of the leftover aluminum wire was 0,43g 1. Calculate the number of...
Assuming an efficiency of 40.10%, calculate the actual yield of magnesium nitrate formed from 119.2 g of magnesium and excess copper(II) nitrate. Mg + Cu(NO3)2 + Mg(NO3)2 + Cu actual yield: OD
Assuming an efficiency of 23.30%, calculate the actual yield of magnesium nitrate formed from 114.1 g of magnesium and excess copper(II) nitrate. Mg + Cu(NO), Mg(NO), + Cu actual yield:
1. How many moles of MgS2O3 are in 225 g of the compound? 2. Determine the empirical formula for a compound that is 64.8% C, 13.6% H, and 21.6% O by mass. 3.A compound is 54.53% C, 9.15% H, and 36.32% O by mass. What is its empirical formula? 4.The Ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. In the first step of the Ostwald process, ammonia is reacted...
Assuming an efficiency of 46.80%, calculate the actual yield of magnesium nitrate formed from 133.6 g of magnesium and excess copper(II) nitrate. Mg+Cu(NO3)2⟶Mg(NO3)2+Cu Mg + Cu ( NO 3 ) 2 ⟶ Mg ( NO 3 ) 2 + Cu actual yield: g
Question When 10.00 g of magneslum are burned, 16.58 g of magnesium oxide are produced. What mass of oxygen gas must have reacted? Provide your answer below FEEDBACKMORE INSTRUCTION SUBMIT