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The human genome contains about 3x10^9 bp of DNA. How many 200-kb fragments would you have...

The human genome contains about 3x10^9 bp of DNA. How many 200-kb fragments would you have to clone into a BAC library to have a 90% probability of in- cluding a particular sequence?

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Answer #1

Size of genome = 3 x 109 bp

= 3 x 109 / 1000

= 3 x 106 kb

Number of 200 kb fragments to be cloned into BAC library = 3 x 106 kb / 200 kb

= 15000 fragments

A total of 15 x 103 fragments of the size 200 kb can be cloned into BAC library from the human genome.

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