Question

Kelly is playing a dice game. She suspects her opponent of using a loaded die. While the opponent is on a snack break, Kelly grabs the die and rolls it 100 times. There were 12 1’s, 15 2’s, 13 3’s, 18 4’s, 20 5’s, and 22 6’s.

At 5% significance, does Kelly have enough evidence to show that her opponent’s die is loaded?

Answer 1

Ans:

Chi square test for goodeness of fit:

H0:The die is not loaded.

Ha:The die is loaded.

	fo	fe	(fo-fe)^2/fe
1	12	16.667	1.307
2	15	16.667	0.167
3	13	16.667	0.807
4	18	16.667	0.107
5	20	16.667	0.667
6	22	16.667	1.707
Total	100	100	4.760

Test statistic:

Chi square=4.760

df=6-1=5

p-value=CHIDIST(4.76,5)=0.4459

As,p-value>0.05,we fail to reject the null hypothesis.

There is not sufficient evidence to conclude that the die is loaded.