A new smartphone just out on the market has a L1 cache with an access time of 1 cycle, an L2 cache with an access time of 5 cycles and DRAM with access time of 30 cycles. The latest benchmarks indicate that for most applications the L1 hit rate is 80% and L2 hit rate is 95%. Compute the Average Memory Access Time for the memory hierarchy in this device.
(More interested in the explanation of how to get the answer, than the answer itself. Thanks in advance!)
Well, the formula for average access time is given as below:
Average Memory Access Time (AMAT)
= Hit Time + Miss Rate * Miss Penalty
Now, there are two levels of cache in this problem, L1 and L2. If we get a miss in L1, we check for the same in L2. And still if there is a miss in L2, we check in the main memory, i.e the DRAM.
So, average access time = Hit_Time_L1 + Miss_Rate_L1 * Miss_Penalty_L1
where Miss_Penalty_L1 = Hit_Time_L2 + Miss_Rate_L2 * Miss_Penalty_L2
Here, Hit_Time_L1 = 1 cycle
Miss_Rate_L1 = 1 - 0.80 = 0.2
Hit_Time_L2 = 5 cycles
Miss_Rate_L2 = 0.05
Miss_Penalty_L2 = 30 cycles
Now, AMAT = 1 + 0.2 * ( 5 + 0.05 * 30) = 1 + 0.2 * 6.5 = 1 + 1.3 = 2.3 cycles
Let me know if you have any doubts in the comments. Please upvote if the answer helped you.
A new smartphone just out on the market has a L1 cache with an access time...
Question 4 - [25 Points] Part (a) - Average Access Time (AMAT) The average memory access time for a microprocessor with One (1) level (L1) of cache is 2.4 clock cycles - If data is present and valid in the cache, it can be found in 1 clock cycle If data is not found in the cache, 80 clock cycles are needed to get it from off- chip memory Designers are trying to improve the average memory access time to...
Base machine has a 2.4GHz clock rate. There is L1 and L2 cache. L1 cache is 256K, direct mapped write through. 90% (read) hit rate without penalty, miss penalty is 4 cycles. (cost of reading L2) All writes take 1 cycle. L2 cache is 2MB, 4 way set associative write back. 95% hit rate, 60 cycle miss penalty (cost of reading memory). 30% of all instructions are reads, 10% writes. All instructions take 1 cycle - except reads which take...
Assume that the: Clock rate is 2 GHz, L1 access time is 1 cycle, L2 access time is 10 cycles, Memory access time is 100 cycles, L1 hit rate is 60%, L2 hit rate is 70%. What is the average memory access time? (4 marks)
a) Calculate the AMAT for a cache system with one level of cache between the CPU and Main Memory. Assume that the cache has a hit time of 1 cycle and a miss rate of 11%. Assume that the main memory requires 300 cycles to access (this is the hit time) and that all instructions and data can be found in the main memory (there are no misses). b) Let us modify the cache system from part (a) and add...
2. Cache hierarchy You are building a computer system with in-order execution that runs at 1 GHz and has a CPI of 1, with no memory accesses. The memory system is a split L1 cache. Both the I-cache and the D-cache are direct mapped and hold 32 KB each, with a block size of 64 bytes. The memory system is split L1 cache. Both the I-cache and the D-cache are direct mapped and hold 32 KB each, with a block...
For a special computer system with 3 levels of cache, here are the hit times and miss % for the different levels of cache Please calculate the access time for this computer system. Hit Miss% L1 Cache 1 Cycle 5% L2 Cache 5 Cycles 10% L3 Cache 20 Cycles 15% Main Memory 100 Cycles 20%
4B, 20%) compare performance of a Processor with cache vs. without cache. Assume an Ideal processor with 1 cycle memory access, CPI1 Assume main memory access time of 8 cycles Assume 40% instructions require memory data access Assume cache access time of I cycle Assume hit rate 0.90 for instructiens, 0.80 for data Assume miss penalty (time to read memory inte cache and from cache to Processor with cache processor) is 10 cycles >Compare execution times of 100-thousand instructions: 4B,...
Compare two designs of a computing system. (i) 1KB L1 cache with misss-rate of 11% and hit-time of 0.62ns. (ii) 2KB L1 cache with miss-rate of 8% and hit-time of 0.66ns . For both the main memory access takes 80ns. (a) Assuming that the L1 hit-time determines the processor cycle time, what are the clock frequencies of the two designs? (b) Calculate the Average Memory Access Time (AMAT) for the two designs
AMAT = Time for a hit + (Miss rate x Miss penalty) For a data cache with a 4% miss rate and a 5-cycle hit latency, calculate the average memory access time (AMAT). Assume that latency to memory and the cache miss penalty together is 100 cycles. Note: The cache must be accessed after memory returns the data.
(a)What is the average memory access time (AMAT) if a cache uses write-back strategy and 20% of the data blocks to be swapped out are dirty. Assume that the miss rate is 15%, the hit time of the cache is 1 cycle and the miss penalty is 8 cycles for the data blocks that are not dirty and 20 cycles for those blocks that are dirty. (b) What is the speedup up if we add a “write-buffer” that eliminates 40%...