What volume of H2O(g) is produced when 2.00 mol of C2H4(g) reacts with oxygen gas at STP?
C2H4(g)+3O2(g)⟶2CO2(g)+2H2O(g)
We are given the following balanced chemical reaction as
C2H4(g)+3O2(g)⟶2CO2(g)+2H2O(g)
1 mole of C2H4 produces 2 moles of H2O
Thus, 2 moles of C2H4 will produce 4 moles of H2O
Now, Each mole of gas occupies 22.4 L at STP
Therefore, volume of H2O = 4 * 22.4 = 89.6 L
What volume of H2O(g) is produced when 2.00 mol of C2H4(g) reacts with oxygen gas at...
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