Calculate the pH of a buffer solution containing phenol and sodium phenoxide in a 1 to 3 ratio.
pKa of phenol=10
Here acid is phenol and conjugate base is sodium phenoxide.
Phenol concentration=[Acid]=C6H5OH=x M
Sodium phenoxide concentration =[Conjugate base]=C6H5ONa]=3x M
pH of a buffer is given by
Henderson - Hasselbalch equation of a buffer :
pH = pKa + log [conjugate base] / [acid]
pH=10 +log[3x]/[x]=10+log(3)=10+0.47=10.47
Thank you.
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