A 2.23 g sample of a non-electrolyte is dissolved in 50.4 g of water. The solution freezes at −1.23℃ . Calculate the molar mass of the solute. (Use Table 12.4)
A 2.23 g sample of a non-electrolyte is dissolved in 50.4 g of water. The solution...
1. 2.9 moles of blue fruit drink mix is added to 1.11 L of water in a pitcher on a hot summer’s day. Assuming a density of 1.00 g/mL and given the vapor pressure of pure water is 25.4 mmHg, what is the vapor pressure of the pitcher of blue fruit drink? 2. A 2.20 g sample of a non-electrolyte is dissolved in 51.1 g of water. The solution freezes at −1.23℃ . Calculate the molar mass of the solute....
when 4.90 g of a non electrolyte solute is dissolved in water to make 505ml of solution at 24 C, the solution exerts an osmotic pressure of 803 torr. what is the molar concentration of the solution? How many moles of solute are in the solution? What is the molar mass of the solute?
When 8.59 g of an unknown, non-volatile, non-electrolyte, X was dissolved in 100. g of benzene, the vapor pressure of the solvent decreased from 100 torr to 97.5 torr at 299 K. Calculate the molar mass of the solute, X.
19.193 g of a non-volatile solute is dissolved in 180.0 g of water. The solute does not react with water nor dissociate in solution. Assume that the resulting solution displays ideal Raoult's law behaviour. At 20°C the vapour pressure of the solution is 17.242 torr. The vapour pressure of pure water at 20°C is 17.535 torr. Calculate the molar mass of the solute (g/mol). Now suppose, instead, that 19.193 g of a volatile solute is dissolved in 180.0 g of...
When 9.31 g of an unknown non-electrolyte is dissolved in 50.0 g of benzene, the boiling point increased by 3.16 degrees C. If the Kbp of the solvent is 2.53 K/m, calculate the molar mass of the unknown solute. The answer is 149 ± 2% looking for explanation how to work this problem
1a: 19.930 g of a non-volatile solute is dissolved in 395.0 g of water. The solute does not react with water nor dissociate in solution. Assume that the resulting solution displays ideal Raoult's law behaviour. At 90°C the vapour pressure of the solution is 521.11 torr. The vapour pressure of pure water at 90°C is 525.80 torr. Calculate the molar mass of the solute (g/mol). 1b: Now suppose, instead, that 19.930 g of a volatile solute is dissolved in 395.0...
17.298 g of a non-volatile solute is dissolved in 265.0 g of water. The solute does not react with water nor dissociate in solution. Assume that the resulting solution displays ideal Raoult's law behaviour. At 90°C the vapour pressure of the solution is 519.57 torr. The vapour pressure of pure water at 90°C is 525.80 torr. Calculate the molar mass of the solute (g/mol).
When (8.61x10^1) g of a non-electrolyte is dissolved in (5.3100x10^2) g of a solvent (with Kb = 0.416°C/m) the boiling point of the solution is 1.50°C higher than the boiling point of the pure solvent. What is the molar mass (in g/mol) of the non- electrolyte solute? Enter your answer in scientific notation with 3 sig figs. Do not include any units in your answer. Do not round any intermediate calculations. Note: Your answer is assumed to be reduced to...
Calculate the freezing point of a solution that contains 5.42 g of glucose, a non-electrolyte, dissolved in 102 g of water.
A solution contains 10.35 g of unknown compound (non-electrolyte) dissolved in 50.0 mL of water. (Assume a density of 1.00 g/mL for water.) The freezing point of the solution is -3.26 ∘C. The mass percent composition of the compound is 60.98% C, 11.94% H, and the rest is O. What is the molecular formula of the compound?