The reaction 2A → B is second order with a rate constant of 51.0/M·min at 24°C.
(a) Starting with [A]0 = 9.30 × 10−3 M, how long will it take for [A]t = 2.70 × 10−3 M?
(b) Calculate the half-life of the reaction.
Answer in Minutes
The reaction 2A → B is second order with a rate constant of 51.0/M·min at 24°C....
The reaction 2A → B is second order with a rate constant of 51.0/M · min at 24 ° C. (a) Starting with [A]0 = 9.30 ×10−3M, how long will it take for [A]t = 2.80 ×10−3M? min (b) Calculate the half-life of the reaction. min
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Be sure to answer all parts. The reaction 2A B is second order with a rate constant of 51.0/M-min at 24°C. (a) Starting with [Alo 8.90 x 10 M, how long will it take for [A],3.30 x 103 M? min (b) Calculate the half-life of the reaction. min
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3 attempts left Check my work Be sure to answer all parts. The reaction 2A + B is second order with a rate constant of 51.0/M min at 24°C. (a) Starting with (Alo = 8.90 X 10 M, how long will it take for (AJ, = 3.50 x 10-M? min (b) Calculate the half-life of the reaction. min
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A.For the following first order reaction, the half-life is 28.3 and the [A]0 = 1.36. Calculate the rate constant.2A -> 3BB.Consider the following reaction. aA + bB -> cCwhose first and second half-lives are 38.2 and 19.1 minutes respectively. If the rate constant is equal to 0.2148 and [A]0 = 16.41, calculate the [A] at t 5.87 minutes.C.A researcher raises the temperature from 46.4 to 66 °C and finds that the rate of the reaction doubles. What was the activation energy (in...
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For a first-order reaction, the half-life is constant. It depends only on the rate constant k and not on the reactant concentration. It is expressed as t 1/2 = 0.693 k For a second-order reaction, the half-life depends on the rate constant and the concentration of the reactant and so is expressed as t 1/2 = 1 k[A ] 0 Part A A certain first-order reaction ( A→products ) has a rate constant of 9.90×10−3 s −1 at 45 ∘...