(c)
A proton is accelerated from rest through a potential difference of 10 kV. A proton has chargeqproton = +1.6 10-19 C and mass mproton = +1.67 10-27 C
i. Calculate the change in potential energy of the proton, in your answer you must explicitly state whether it is a gain or loss in potential energy.
ii. Calculate the final velocity of the proton.
(c) A proton is accelerated from rest through a potential difference of 10 kV. A proton...
A proton of mass m = 1.67 x 10-27 kg and charge q = 1.60 x 10-19 C is accelerated from rest through a potential difference of 4000 V. What final velocity does it achieve? A proton of mass m = 1.67 x 10-27 kg and charge q = 1.60 x 10-19 C is accelerated from rest through a potential difference of 4000 V. What final velocity does it achieve?
A proton (m= 1.67e-27 kg) is accelerated from rest through a potential difference of 11.5 kV before entering a velocity selector. If the B- field of the velocity selector is perpendicular to the velocity and the electric field (E) has a magnitude of 3.5e6 N/C, what is the required magnitude of the magnetic field (B) if the proton is undeflected?
A)A proton is accelerated from rest through a potential difference of 25707 V. What is the kinetic energy of this proton after this acceleration? The mass of a proton is 1.673 × 10−27 kg and the elemental charge is 1.602 × 10−19 C. Answer in units of J. B) What is the speed of the proton after this acceleration? Answer in units of m/s.
A proton is accelerated from rest through a potential differences of 1.0 kV. It enters a uniform magnetic field of 4.5 mT that is initially perpendicular to its velocity. (a) Find the radius of the proton's circular path (b). Calculate the period of revolution of the proton.
A deuteron is accelerated from rest through a 10-kV potential difference and then moves perpendicularly to a uniform magnetic field with B = 1.6 T. What is the radius of the resulting circular path? (deuteron: m = 3.3 Times 10^-27 kg, q = 1.6 Times 10^-19 C). Give your answer in millimeters) Two long straight parallel wires separated by a distance of 20 cm carry currents of 30 A and 40 A in opposite directions. What is the magnitude of...
An electron in a cathode ray tube is accelerated through a potential difference of 8.0 kV. What kinetic energy does the electron gain in the process? (e = 1.6 × 10−19 C) 1.3E–15 J 1.0E–21 J 1.0E–15 J 5.0E–16 J 1.3E–21 J
1.A proton (q=e, mp=1.67 x 10-27kg) is accelerated from rest through a potential difference of 1.0 MV. What is the final speed?
A proton (mp = 1.67 x 10-27 kg) is accelerated from rest by a potential difference of 1000 V. What is the DeBroglie wavelength of the proton? 0 1.44x 10-13 m. 9.06 x 10-13 m O 1.28 x 10-12 m O 2.87 x 10-11 m 3.88 x 10-11 m
A proton, that is accelerated from rest through a potential of 13.0 kV enters the velocity filter, consisting of a parallel-plate capacitor and a magnetic field, shown below. The E-field between the parallel capacitor plates is 3.9·105 N/C. What B-field is required so that the protons are not deflected? (Ignore relativistic effects for high velocities.)
A stationary proton is accelerated through a potential difference of 83.5 KV . what speed did the proton acquire by using work-energy theorem.