Do Both Please
it took .0093 moles NaOH to neutralize an impure sample of citric acid. how many grams of citric acid are in the sample H6C6H5O7+3NaOH -> 3H2O + Na3C6H5O7
which if the following is true in this acid base titration when the moles of hydrogen ion equal the moles of hydroxide ion? naturalization equivalency a salt is produced all the above
H3C6H5O7+3NaOH -----------------> 3H2O + Na3C6H5O7
here the mole are for the citric acid is 1 and the NaOH are 3 moles
from the equation
3 mol NaOH ----------------------------> 1 mol H3C6H5O7
0.0093 mol ------------------------------->?
=> 0.0093 * 1 / 3
=> 0.0031 moles
mass of citric acid is required is = moles * molar mass
mass = 0.0031 mol * 192.124g/mol => 0.59558 grams
answer => 0.6 grams
when the no of moles of the H+ are equal to the OH- ion and then neutralization reaction will occurs i.e the total amount of the H+ are reacted with the OH- and remains unreacted in the reaction
Do Both Please it took .0093 moles NaOH to neutralize an impure sample of citric acid....
Citric acid (H3C6H5O7) a triprotic acid, reacts with sodium hydroxide according to the reaction equation below. What volume of 0.800 M NaOH in liters, is required to neutralize 3.00L of a 0.400 M solution of citric acid? enter your answer to the hundredths place. H3C6H5O7(s)+3NaOH(aq) --> Na3C6H5O7(aq)+3H2O(l)
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