Given the following instruction:
LDURB X1, [X2, 0x4]
Where X1 = 0x123456789abcdef0 and X2 = 0x0 and memory currently has the following data:
Address Data
0x0 0xDEADBEEF12345678
0x8 0xBA5EBA11F005BA11
What will be left in X1 after the instruction executes (assume little endian): ______
Answer :- The LDURB instruction will load a byte from the address (X2+4). So a byte from address 0x04 will be loaded to X1. The value is zero extended in X1.
Thus X1 = byte value at 0x04 = 0xEF. After zero extension,
Given the following instruction: LDURB X1, [X2, 0x4] Where X1 = 0x123456789abcdef0 and X2 = 0x0...
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