Question

Consider a thick-walled cylinder of inner radius r_i and outer radius r_o and thickness t . This cylinder is subject to a centrifugal force E = mw2T (= constant rotation sped) from its longitudinal axis.

If we know the radial stress \sigma_r,the hoop stress \sigma_{\theta } ,the hoop strain \epsilon_{\theta } , the radial strain \epsilon_{r} :

\sigma_{r} = \frac{3 + \nu}{8}\rho\omega^2\left(r_o^2+ r_i^2 - \frac {r_i^2r_o^2}{r^2}-r^2 \right )

\sigma_{\theta} = \frac{3 + \nu}{8}\rho\omega^2\left(r_o^2+ r_i^2 + \frac {r_i^2r_o^2}{r^2}-\frac{1+3\nu}{3+\nu}r^2 \right )

\epsilon_{\theta} = \frac{1}{E}\left(\sigma_{\theta} - \nu \sigma_r \right )= \frac{u_r}{ r}

\epsilon_{r} = \frac{1}{E}\left(\sigma_{r} - \nu \sigma_{\theta} \right )дит

where \nu is the Poisson ration and u_r is the radial displacement.

How to compute the TOTAL POTENTIAL ENERGY |TPE| = \| \mathcal{U} - \mathcal{P}\| ?

N.B. : \mathcal{P} is the work done by external forces

         \mathcal{U} is the elastic internal potential energy



E = mw2T
= constant rotation sped









дит




0 0
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Answer #1

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