1. Phenotypic ratio is: 2:1 (aristapedia antennae : wild type). You have to do 815/408 = 1.9975 = 2
The phenotypes are wild type and aristapedia antennae.
You mate two Fi flies and observe the following results of the F2 generation. Mal Tan body Male. ...
Genetic Linkage The six genes listed below are all located on Chromosome 2 of Drosophila melanogaster. Your goal is to construct a genetic map of Chromosome 2. That is, determine the order of these genes along chromosome 2 and the map distance in centimorgans between each gene. To complete this task, you will be given the results of a variety of two-point test crosses involving these genes. For each test cross you may assume that the female is heterozygous and...
recalling that wild type is tan body, red eyes, straight wings and straight antennae, the data is consistent with the logical hypothesis that mutant trait-pick a mutant-is -autosomal or sexlinked-, -dominant or recessive-. using the f2 geb data and assuming we want to fail to reject the null hypothesis abd support "logical" hypothesis for this mutant trait, for the chi square goodness of fit test what is the chi square statistical value? (value should be to the hundreths) Here is...
3) Dihybrid cross: The dark-bodied and rudimentary winged genes are on two different autosomal chromosomes. We will use this cross to determine the ratios of phenotypes in the F2 generation when there are two genes involved. 3.1) Use the following symbols to write out the cross: Male: Female: 0 Dark body color (ebony) = Wild-type body color: E or E+ Rudimentary wings- (vestigial wings= v) Wild-type wings: V or V+ 3.2) What would the cross look like if we mated...
2. You cross a homozygous wildtype female Drosophila (fruit fly) with a male that has a black body (bb). You mate two of the F1 (first generation) flies and examine the F2 (second generation) offspring. The phenotypes can be seen in the table below. a. Draw a pedigree to show the P, F1, and F2 generations. You only need to draw one fly with each phenotype for the F2 generation. seen in this cross. the expected values for a cross...
3) Dihybrid cross: The dark-bodied and rudimentary winged genes are on two different autosomal chromosomes. We will use this cross to determine the ratios of phenotypes in the F2 generation when there are two genes involved. 3.1) Use the following symbols to write out the cross: Male: 3 Female: 9 Dark body color (ebony) = e Wild-type body color: E or E+ Rudimentary wings- (vestigial wings= v) Wild-type wings: V or V+ 3.2) What would the cross look like if...
The phenotype of vestigial (short) wings (vg) in Drosophila melanogaster is caused by an autosomal recessive mutant allele that independently assorts with an autosomal recessive mutant allele for hairy (h) body. A parental cross was made between a fly that is homozygous for normal wings with a hairy body and a fly with vestigial wings that is homozygous for normal body hair. The wild-type F1 flies were crossed to each other and produced 1536 offspring. The phenotypes of the F2...
The phenotype of vestigial (short) wings (vg) in Drosophila melanogaster is caused by an autosomal recessive mutant allele that independently assorts with an autosomal recessive mutant allele for hairy (h) body. A parental cross was made between a fly that is homozygous for normal wings with a hairy body and a fly with vestigial wings that is homozygous for normal body hair. The wild-type F1 flies were crossed to each other and produced 1536 offspring. The phenotypes of the F2...
We crossed pure-bred female flies with yellow body and forked-shaped bristles with male flies extra bristles. The subsequent F1 flies showed all normal phenotypes except that all of the F1 males are yellow-body. We crossed again the normal F1 females with males homozygous for yellow body, extra bristles, and forked bristles as a testcross. The number of each category of F2 progeny is shown below. The mutant allele for yellow body is y; the mutant allele for extra bristles is...
Please show work. 2. You mate a female fly with a black body, purple eyes, and vestigial wing size to a wild- type male. These three alleles are located on chromosome II (autosome) in Drosophila. You testcross one of the Fi females to a male with all three mutations and record the results from the testcross in following table. Phenotype # of each phenotype Body color eye color wing size red red red red 900 le normal vestigial 90 50...
If an apterous female fruit fly with wild type (+) red eyes is crossed with a white eyed male with normal wild type wings, what is the resting F1 generation? Please show on a punnet square.Also what is the punnet dihybrid cross for the F2 generation. Note: the recessive white eyed allele is X-linked while the apterous (wingless) recessive allele is NOT x-linked. SO to summarize: male with recessive white eyes and with normal wild type wings and a recessive...