Homework Answers
The ALU output for the branch-on-equal instruction is used to determine the PC+4 added with the sign-extended, lower 16 bits of the offset shifted left by two in the instruction field, as the new branch target address if the result of the subtraction in the ALU is not zero.
False
New branch target address if the result of the subtraction in the ALU is possible to zero.
While doing subtraction Zero is the output of the ALU then we understand that PC+4 or BTA to write new PC.
Option a
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The ALU output for the branch-on-equal instruction is used to determine the sign-extended, lower ...
Add 9 MUX 4 4 Addresult ALU Shift left 2 RegDst Branch MemRead Instruction (31-26) Control...
Add 9 MUX 4 4 Addresult ALU Shift left 2 RegDst Branch MemRead Instruction (31-26) Control Memto Reg ALUOD MemWrite ALUSC RegWrite Instruction [25-21) Read PC Read address register 1 Read Instruction (20-16] MUX1 MUX Zero ALU ALU MUX3 M Instruction (31-0) Instruction memory Road Address data Read data 1 register 2 Write Read register data 2 Write data Registers result Instruction (15-11] Fox SX) Data Write data memory 16 32 Instruction (150) Sign- extend ALU control Instruction (5-0)
MCS) Add Addresult ALU Shift left 2 RegDst Branch MemRead MemtoReg Instruction (31-26] Control ALUOP MemWrite...
MCS) Add Addresult ALU Shift left 2 RegDst Branch MemRead MemtoReg Instruction (31-26] Control ALUOP MemWrite ALUS RegWrite PC instruction (25-21] Instruction (20-16) Read address Instruction (31-0) Instruction memory Read register 1 Read Read data 1 register 2 Write Read Zoro ALU ALU result Address Read data instruction (15-11] register data 2 x3) Write data Registers Write Data data memory Instruction 15-01 16 Sign- extend ALU control Instruction (5-0) With regards to the single cycle implementation (as shown in the...
Modify the circuit to support a MFCC instruction. MFCC Rd instruction: Move From Condition Codes MFCC copies into the fo...
Modify the circuit to support a MFCC
instruction.
MFCC Rd instruction: Move From Condition Codes
MFCC copies into the four rightmost bits of Rd the values of the
ALU signals Carry (C), Overflow (O), Zero (Z) and Negative (N) as
they were set by the previous R- type instruction. The remaining 28
bits of Rd are set to zero.
Describe the changes and additions needed for the
single-cycle MIPS processor datapath and control to support this
instruction.
Hints:
1) MFCC...
Add EX ALU Add dresult Shift left 2 Regst Branch MomRoad Instruction (31-26) MemtoReg Control ALUOO...
Add EX ALU Add dresult Shift left 2 Regst Branch MomRoad Instruction (31-26) MemtoReg Control ALUOO MemWrite ALUST RegWrite instruction [25-21] Read register 1 Read instruction (20-16) Read data 1 register 2 Write Read data 2 instruction (15-11) register Write data Registers Read address Zero ALU ALU Instruction (31-0) Instruction memory result Address Read data Write Data data memory Instruction (15-01 16 32 Sign- extend ALU control Instruction (5-0) With regards to the single cycle implementation (as shown in the...
(o x Add Addresult ALU Shift left 2 Regst Branch MemRead Instruction (31-26) MemtoReg Controll ALUOP...
(o x Add Addresult ALU Shift left 2 Regst Branch MemRead Instruction (31-26) MemtoReg Controll ALUOP MemWrite ALUSC RogWrite Instruction [25-21] Read register 1 Read Instruction (20-16) Read data 1 register 2 Write Read Instruction (15-11) Write data Registers PC Read address Zoro ALU ALU Instruction (31-0) Instruction memory result Address Read data register data 2 **039 -25 Write Data data memory Instruction (15-01 16 Sign- extend ALU control Instruction 15-01 With regards to the single cycle implementation (as shown...
6. Consider a datapath similar to the one in figure below, but for a processor that only has one type of instruction: unconditional PC-relative branch. What would the cycle time be for this dat...
6. Consider a datapath similar to the one in figure below, but for a processor that only has one type of instruction: unconditional PC-relative branch. What would the cycle time be for this datapath? PCSrc Add ALU Add result Shift +( left 2 Read register 1 ALUSrc, 4 ALU operation PCRead PC-address Read data 1 Registers Read data 2 MemWrite Zero ALU ALU-I Address MemtoReg Instruction register 2 Instruction | Write Read data-M register Write Lu memory Write Data data...
Question 5 0.25 pts What is the value of the MemWrite control signal? Question 6 0.25 pts What is the value of the ALUSrc control signal? Add Add Sum--(1 4 Shift left 1 Branch MemRead Instruction [6-...
Question 5 0.25 pts What is the value of the MemWrite control signal? Question 6 0.25 pts What is the value of the ALUSrc control signal? Add Add Sum--(1 4 Shift left 1 Branch MemRead Instruction [6-0] ControMemtoReg MemWrite ALUSrc RegWrite Instruction [19-15]Read Read register 1 Read Read data! PCaddress Instruction [24-20] Zero ALU ALU result register 2 Instruction 31-0 Instruction [11-7 Read1 Address data | Write Read register daiaALU | M Instruction memory Write data Registers Write Data data...
3. Assume the processor data path show below. XE30 Add Add ALU result Shift left 2...
3. Assume the processor data path show below. XE30 Add Add ALU result Shift left 2 RegDst Branch MemRead Instruction (31-26] RegSrc Control ALUOP Mem Write ALUSrc RegWrite PC Instruction (25-21) Read address Instruction (20-16] Instruction [31-0) Instruction instruction (15-11) memory Read register 1 Read data 1 Read register 2 Write Read register data 2 Write data Registers Zero ALU ALU result Read Address data OX OX3) 3x) Write Data data memory Instruction [15-0) 16 32 Sign- extend ALU control...
Assume that ‘slt $1, $2, $3’ is executed with the implementation in the picture. Identify the value of the 9-bit control...
Assume that ‘slt $1, $2, $3’ is executed with the implementation
in the picture. Identify the value of the 9-bit control
signals.
Add u X ALU result 4 Add Shift left 2 RegDst Branch MemRead MemtoReg Control ALUOP Instruction [31-26 MemWrite ALUSRC RegWrite Instruction [25-21] Read register 1 Read Read PC address Instruction [20-16] data 1 Read Zero register 2 Instruction ALU ALU 31-0] Instruction memory Read data M Read Address Write result u M Instruction [15-11] register data 2...
it is the same question A block diagram of MIPS architecture is given below. What is...
it is the same question
A block diagram of MIPS architecture is given below. What is the value of the control bit for each MUX during the execution of the given instruction? Note, you may use N/Aif MUX output is not usefu Add MUX 4 ALU Add, result Shift left 2 RegDst Branch MemRead Instruction (31-26] Control Memto Reg ALUOP Mem Write ALUSrc RegWrite Instruction [25-21) PC Read address Instruction (20-16] MUXT Read register 1 Read Read data 1 register...
Add 9 MUX 4 4 Addresult ALU Shift left 2 RegDst Branch MemRead Instruction (31-26) Control Memto Reg ALUOD MemWrite ALUSC RegWrite Instruction [25-21) Read PC Read address register 1 Read Instruction (20-16] MUX1 MUX Zero ALU ALU MUX3 M Instruction (31-0) Instruction memory Road Address data Read data 1 register 2 Write Read register data 2 Write data Registers result Instruction (15-11] Fox SX) Data Write data memory 16 32 Instruction (150) Sign- extend ALU control Instruction (5-0)
MCS) Add Addresult ALU Shift left 2 RegDst Branch MemRead MemtoReg Instruction (31-26] Control ALUOP MemWrite ALUS RegWrite PC instruction (25-21] Instruction (20-16) Read address Instruction (31-0) Instruction memory Read register 1 Read Read data 1 register 2 Write Read Zoro ALU ALU result Address Read data instruction (15-11] register data 2 x3) Write data Registers Write Data data memory Instruction 15-01 16 Sign- extend ALU control Instruction (5-0) With regards to the single cycle implementation (as shown in the...
Modify the circuit to support a MFCC
instruction.
MFCC Rd instruction: Move From Condition Codes
MFCC copies into the four rightmost bits of Rd the values of the
ALU signals Carry (C), Overflow (O), Zero (Z) and Negative (N) as
they were set by the previous R- type instruction. The remaining 28
bits of Rd are set to zero.
Describe the changes and additions needed for the
single-cycle MIPS processor datapath and control to support this
instruction.
Hints:
1) MFCC...
Add EX ALU Add dresult Shift left 2 Regst Branch MomRoad Instruction (31-26) MemtoReg Control ALUOO MemWrite ALUST RegWrite instruction [25-21] Read register 1 Read instruction (20-16) Read data 1 register 2 Write Read data 2 instruction (15-11) register Write data Registers Read address Zero ALU ALU Instruction (31-0) Instruction memory result Address Read data Write Data data memory Instruction (15-01 16 32 Sign- extend ALU control Instruction (5-0) With regards to the single cycle implementation (as shown in the...
(o x Add Addresult ALU Shift left 2 Regst Branch MemRead Instruction (31-26) MemtoReg Controll ALUOP MemWrite ALUSC RogWrite Instruction [25-21] Read register 1 Read Instruction (20-16) Read data 1 register 2 Write Read Instruction (15-11) Write data Registers PC Read address Zoro ALU ALU Instruction (31-0) Instruction memory result Address Read data register data 2 **039 -25 Write Data data memory Instruction (15-01 16 Sign- extend ALU control Instruction 15-01 With regards to the single cycle implementation (as shown...
6. Consider a datapath similar to the one in figure below, but for a processor that only has one type of instruction: unconditional PC-relative branch. What would the cycle time be for this datapath? PCSrc Add ALU Add result Shift +( left 2 Read register 1 ALUSrc, 4 ALU operation PCRead PC-address Read data 1 Registers Read data 2 MemWrite Zero ALU ALU-I Address MemtoReg Instruction register 2 Instruction | Write Read data-M register Write Lu memory Write Data data...
Question 5 0.25 pts What is the value of the MemWrite control signal? Question 6 0.25 pts What is the value of the ALUSrc control signal? Add Add Sum--(1 4 Shift left 1 Branch MemRead Instruction [6-0] ControMemtoReg MemWrite ALUSrc RegWrite Instruction [19-15]Read Read register 1 Read Read data! PCaddress Instruction [24-20] Zero ALU ALU result register 2 Instruction 31-0 Instruction [11-7 Read1 Address data | Write Read register daiaALU | M Instruction memory Write data Registers Write Data data...
3. Assume the processor data path show below. XE30 Add Add ALU result Shift left 2 RegDst Branch MemRead Instruction (31-26] RegSrc Control ALUOP Mem Write ALUSrc RegWrite PC Instruction (25-21) Read address Instruction (20-16] Instruction [31-0) Instruction instruction (15-11) memory Read register 1 Read data 1 Read register 2 Write Read register data 2 Write data Registers Zero ALU ALU result Read Address data OX OX3) 3x) Write Data data memory Instruction [15-0) 16 32 Sign- extend ALU control...
Assume that ‘slt $1, $2, $3’ is executed with the implementation
in the picture. Identify the value of the 9-bit control
signals.
Add u X ALU result 4 Add Shift left 2 RegDst Branch MemRead MemtoReg Control ALUOP Instruction [31-26 MemWrite ALUSRC RegWrite Instruction [25-21] Read register 1 Read Read PC address Instruction [20-16] data 1 Read Zero register 2 Instruction ALU ALU 31-0] Instruction memory Read data M Read Address Write result u M Instruction [15-11] register data 2...
it is the same question
A block diagram of MIPS architecture is given below. What is the value of the control bit for each MUX during the execution of the given instruction? Note, you may use N/Aif MUX output is not usefu Add MUX 4 ALU Add, result Shift left 2 RegDst Branch MemRead Instruction (31-26] Control Memto Reg ALUOP Mem Write ALUSrc RegWrite Instruction [25-21) PC Read address Instruction (20-16] MUXT Read register 1 Read Read data 1 register...
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