If a particular coordinate is moving with a velocity u'x and a particle moves in that x' frame with a velocity ( say suppose v). Then taking these two points let's say an observer who is at rest will see the velocity ( relative velocity) in the form of equation
Vrelative =( ux' + v) /( 1+ { ux'. v }/c2)
So here spaceship --> as the moving coordinate.
The Missile fired --> the particle moving with velocity v.
Since they are moving in the same direction so we have ux' = 0.8c and v = 0.5c
Now relative velocity = ( 0.8 c + 0.5c) /( 1 + 0.8*0.5 c2/c2)
= 1.3c/1.4
= 0.928c = approximately 0.93c Answer (c)
N11. A spaceship is moving away from an asteroid with a speed of 0.80c relative to the aster- oid...
please help with immediacy.
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this is one question but with multiple choice questions,
sorry.
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