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1 Normal 1 No Spac.. Heading 1 Heading2 Title nt tyle 6 The Data table below depicts FBI national crime report data over a ni

this is question number 6
and number 7 is connected to number 6

70629 71849 73445 70310 662314 658379 643472 6 145158 145496 141375 a. What level is the data? (4pts) b. Is this a qualitativ

question number 7

didn't realize that number 7 was connected to number 6 Thanks

1 Normal 1 No Spac.. Heading 1 Heading2 Title nt tyle 6 The Data table below depicts FBI national crime report data over a nine (9) year period for AA juvenile acrests related to the indicated crimes I Astest under 18 Robbery Year AggravatedT 593101 588118 603790 612346 59977 58322 59127 8960 61869 70629 71849 73445 70310 165232 163889 153415 146268 153333 152689 145158 145496 45787 662314 658379 643472 9 a. What level is the data? (4pts) b. Is this a qualitative or quantitative data? (4pts) c. What is the outcome variable(s)? What is the Predictor(s) variable? (4pts) d. Can the findings be generalızed to local communities? Briefly Explain (5pts) e. Determine the mean and StD for each variable: (Show equations used) (15pts) Standard Deviation Mean Variable Arrest under 18 Robb Aggravated Assault Equations: Mean PrtSc F10 6 7 890 TYUI JK FG
70629 71849 73445 70310 662314 658379 643472 6 145158 145496 141375 a. What level is the data? (4pts) b. Is this a qualitative or quantitative data? (Apts) c. What is the outcome variable(s)? What is the Predictor(s) variable? (4pts) d Can the findings be generalized to local communities? Briefly Explain (5pts) e. Determime the mean and StD for ceach vanable: (Show eqyations used) (15pts) Variable Arrest under 18 Ro Aggravated Assauit Equations: Mean 7. Determime the Pearson correlation significance (p-value) of each predictor variable on the outcome variable from the test results. Indicate strong or weak association for each variable value and indicate which value(s) is significant at the 05 level? (Use correlation and significance tables) (12pts) Arrest under 18 p (Strong/ weak) circle choice Robbery p (Strong/ weak) circle choice Ag Assault p--(Strong/ weak) circle choice PrtSc 凸 F11 F10 0 9 8 6 5 TY U I
0 0
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Answer #1
Arrests Robbery Assault
593101 59977 165232
588118 58322 163889
603790 59127 153415
612346 58960 146268
645787 64869 153333
662314 70629 152689
658379 71849 145158
643472 73445 145496
596511 70310 141375

Q7:

Robbery P 0.704721466
Ag Assault P= -0.411540054

The sample size is n -10, so then the number of degrees of freedom is df n-2 10-2 8 test is: r0.632 Observe that in this case

tc= 0.632
Robbery P 0.704721466 Strong
Ag Assault P= -0.411540054 Weak
tc= 0.632
Robbery P =CORREL(A2:A10,B2:B10) =IF(F3>$F$2,"Strong","Weak")
Ag Assault P= =CORREL(A2:A10,C2:C10) =IF(F4>$F$2,"Strong","Weak")
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