Question

Question 5 2 pts Following diagram illustrates the process of writing a register. Suppose all 5 bits for "Register number" are high voltage and all 32 bits for "Register data" are low voltage. And we assume high voltage means 1 and low voltage means 0. Write 0 Register 0 n-to-2n. decoder Register number Register 1 Register n-2 Register n-1 Register data Question:s .When we apply high voltage to "Write" signal, which register(s) have their C input to be at high voltage? . We then lower the voltage of "Write" signal to finish the register write. Which register is written with what value?

Answer 1

Here using decoder..if register number = 11111. Then decoder output for 2^n - 1 = 1. And remaining all outputs should be zero.

1) when write signal = 1. The register n - 1 of the 'c' input could be high. And the remaining all registers 'c' inputs are low. Because input coming to register 'c' input is anded.

2)when write signal = 0. The register n - 1 is written with the register data.