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final answwr is [HOBr]= 0.0001 M, [OBr]= 0.0000037 M and [Br2] = 0.000000183 M
10- mole of bromine, BI2, is added to a liter of water. The resulting pH is 7.0. Give equilibrium, n that the following react
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and the pH =7.0 This means at u1 M up e tce table we have (04 Change Pueu duot - bx to That is, k B52= 9.18174022 x10 x - Lo80.ooo toM 2 부 0. 0000001 83M) [HoBs) = 0 ,0000998140022- 3.7x1o 9 x .0000 9981 70022 3.69322908 Χ00M

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final answwr is [HOBr]= 0.0001 M, [OBr]= 0.0000037 M and [Br2] = 0.000000183 M 10- mole of bromine, BI2, is added to a liter of water. The resulting pH is 7.0. Give equilibrium, n that the followi...
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