Question

6. Identify the significance of standard deviation in data analytics using Table 5A data as a reference.

Data Table 5A

Standard Deviation Table
Coder Status	Mean	N	Standard Deviation
Inpatient Coding Specialist II	93.0000	3	5.0000
Inpatient Coding Specialist I	89.5000	2	0.70711
Ambulatory Surgery Coding Specialist	73.3333	3	6.4291
Total	84.7500	8	10.51190

7. Calculate the mean length of stay and the median age using Table 6A. Show your work.

Patient #	Age	Length of Stay (LOS)
Case 1	52.6	10
Case 2	81.9	12
Case 3	74.7	8
Case 4	23.8	4
Case 5	27.9	5
Case 6	42.5	6
Case 7	55.2	7
Case 8	77.0	9
Case 9	81.2	10
Case 10	53.8	8

Answer 1

7.

• Mean is computed by dividing the sum of all the values by the total number of values. Arithmetic mean is represented by $\bar{X}$ .

Formula :

$\bar{X}= \frac{Sum\: of\, the\, values\left ( \sum x \right )}{Number \, of\, the\, values\left ( n \right )}$

To calculate the mean length of stay,

$\bar{X}= \frac{10 + 12 + 8 + 4 + 5 + 6 + 7 + 9 + 10 + 8}{10}$

$\bar{X}= \frac{79}{10}= 7.9$

Hence, the mean of the length of stay is 7.9

• Median of a set of values is the middle- most value when data is arranged in ascending order of magnitude.

Formula :  

$M= \left ( \frac{n+1}{2} \right )^{th}\, observation\, or\, item$

First, arrange the data in ascending order of magnitude.

23.8 , 27.9 , 42.5 , 52.6 , 53.8 , 55.2 , 74.7 , 77 , 81.2 , 81.9

$M= \left ( \frac{10+1}{2} \right )^{th}\, observation\, or\, item$

$M= \left ( \frac{11}{2} \right )^{th}\, observation\, or\, item$

th observation or item

In ascending order the numbers are 23.8, 27.9, 42.5, 52.6, 53.8, 55.2, 74.7, 77, 81.2, 81.9 . There are 10 total numbers, so the 5th and 6th numbers are used to figure the median. (53.8 + 55.2) / 2 = 54.5

Hence, The median age is 54.5.