In each reaction box, place the best reagent and conditions from the list below.
1) excess NaNH2
2) Br2, 1-equiv.
Explanation: NaNH2 is a strong base which gives dehydrohalogenation and produces alkyne as product which on further reaction with 1 equiv. Br2 produces dibromoalkene as product.
In each reaction box, place the best reagent and conditions from the list below. In each reaction box, place the best re...
In each reaction box, place the best reagent and conditions from the list below. In each reaction box, place the best reagent and conditions from the list below 1) 2) 3) 4) PBrs H2, Lindlar catalyst Вн-THF CH5CH2Br NaBH4 CH3Br H2O, H2SO4, HgSO4 Na, NHa () НаОг, NaOH, Hzо excess NaNH2 HBr Br2 2 equiv. NaNH2
In each reaction box, place the best reagent and conditions from the list below 1) 2) 3) 4) HBr PВrg Вн/THF excess NaNH2 H20, H2SO4, HgSO4 NaBH4 CH3Br H2, Lindlar catalyst H2O2, NAOH, H20 СH-CH2Br Br2 Na, NH3 () 2 equiv. NaNH2
In each reaction box, place the best reagent and conditions from the list below. In each reaction box, place the best reagent and conditions from the list below. 2 equiv. NaNHz excess NaNH2 CH3Br H20, H2SO4, HgSO4 Na, NH3 (1) H2O2, NaOH, H2O NaBH4 HBr Br2 CH3CH2Br H2. Lindlar catalyst BH3/THF PBr3
In each reaction box, place the best reagent and conditions from the list below 1) excess NaNH2 2) 3) 4) PBrs H2, Lindlar catalyst ВН+THF 2 equiv. NANH2 CH3Br Hо, НSO4, Hgso NaBH Na, NH3 () HаОг, NaOH, H>o HBr CH3CH2Br Br2
In each reaction box, place the best reagent and Conditions from the list below. H C C H Br Br H2, Lindlar catalyst H20, H2SO4, Hgso4 CH3CH2Br HBr 1-equiv BH3/THF HBr 2-equiv CH3CH2CH2Br CH3Br H202/NaOH Br2 1-equiv NaOH NaNH2 Br2 2-equiv
In each reaction box, place the best reagent and conditions from the list below.PBr3 H2,Lindlar cat. BH3/THF CH3Br Br2,1 ?equiv. Br2,2-equiv. NaBH4 excess NaNH2 NaOH H3O+ HBr, 2-equiv. HBr, 1-equiv.
In each reaction box, place the best reagent and conditions from the list below. 1) Br2 2) 2 equiv. NaNH2 3) CH5CH2Br 4) Ha. Lindlar catalyst PBrs HЕг Вн-THF excess NANH2 CH Br H2O, H2SO4, HgSO4NaBH4 H202. NaOH, H20 Na, NH3 ()
In each reaction box, place the best reagent and conditions from the list below. BH3/THF PBr3 excess NaNH2 HBr H20, H2SO4, HgSO4 NaBH4 CH3BT H2O2, NaOH, H20 Hz, Lindlar catalyst CH3CH2Br Br2 Na, NH3 (1) 2 equiv. NaNH2
In each reaction box, place the best reagent and conditions from the list below. You have the wrong reagent for the final step. An oxidizing agent is necessary to convert the boron functional group into an enol, which will tautomerize to the aldehyde. 1) Br2 DEDY 2) excess NaNH2, then H20 3) BH3/THF 2 equiv. NaNH2 H2, Lindlar catalyst bromocyclohexane HBr H20, H2SO4, HgSO4 NaBH4 CH3Br CH3CH2Br H2O2, NaOH, H20 SOCI2
In each reaction box, place the best reagent and conditions from the list below. 100 0 1) 2) 3) 0 Br CH3Br CH3CH2CH2Br BHyTHF NaOH HBr 1-equiv NaNH2 H2, Lindlar catalystH2O, H2SO4, HgS04 Br2 1-equiv HBr 2-equiv. CH3CH28r Br2 2-equiv H20 NaOH