Question

Physical Chemistry

rating based in correction please

Consider a Carnot cycle in which the working substance is 0.10 mol of perfect gas molecules, the temperature of the hot source is 373 K, that of the cold sink is 273 K; the initial volume of gas is 1.00 dm', which doubles over the course of the first isothermal stage. For the reversible adiabatic stages it may be assumed that VT3/2 = constant. a) calculate the volume of the gas Vs and Vc); b) calculate the volume of the gas after stage 3 (VD) by considering the reversible adiabatic compression from the starting point; c) for each of the four stages of the cycle, calculate the heat transferred to or from the gas; d) Explain why the work done is equal to the difference between the heat extracted from the hot source and that deposited in the cold sink; e) calculate the work done over the cycle and hence the efficiency n. f) confirm that your answer agrees with the efficiency from n = 1 - Tc/Th. (20 pts)

Answer 1

Question is related to Carnot cycle.

Solution The given data are - males of potestans o-lo mal Teubedlace of best soundi_(TW) = 393K -- Temperature of cold ank (T) 2 273K.............. The initial raleme of gas (VA) = 1.00 dins lliter Remigilale adiabatic. helseful OL VIA Cowgtout- Now we_delow a como cucle as- Isothermal process (PAV) as (Peuro) . adiabatic poroceat - w Peve) Povo) 9. TO V Recocers AB z folusual expansion Be a Adiabatic expansion CD z wcthcremal confocession? D . Adiabolic counkousasion VAZ Vp. z liten 2 litu (gren] (given) Pouss BC follow with a constant

Mence far (PB, VB) and (Pelo) - VBT / constant VTR z. contact Hence Ve The = vel ř - (02319) 20:6261 Ve 23:19 LMS 0.6221 Paut (a) Hence the valuma VB z 2litree, Vc = 3 19 litece. Post (6) - Per cott adiabad PHPOSE DA is adiabatte compussion hence it follows - 7² zlonstant Voter constant VAT / a constant Hence e Voth 2 VNT

57 → Voz (1.3663) Voz 1.5970 Vpz-1-60 litere - Free vр 1-60.gias Part (0) Process AB W Isetlumal, expansion dronce -A122.0 from. Fiast lavo of teymuodognomie Aux qrW 9-W 2-{-net enn The ne Telefon = 0.70XBX373.2013) 9. = 2.12 aolitri -W z wz-2.12 Hence qy is leat focouplesed to the systemet. Process B.C and of drie adiabatic Prouss hence has these puoleEsqze -- F921. pool8 CD 1024,W 12-We-l-ne[en] anRice (

--- 2 0-10 X 0.0821X23 1 60 (3.19 --9- -00X0.082LX 243 en/3:19) (160 -9,2 - 1.54 x.-W » We 1.54 - Hence on process co heat transfered from the system Part (2) - from above work done in process AB (Wi) 2 -2:12 atlete - Depose DC.) 21:54 am lite Now wark.doue in þuvcele BC (Mg), BHOR (273-373] w process dA (wa) 2.0-10R (375–273] Total work We Wit Wet Wg the Wz-2012 +7.54 + for f273-375) - 0-10{273–37.5) Wz-212 + 1:59 - Difference betireen heat extracted from sowice and that deposited to the sink Wlz ~0.58 atomuliters

Parct (e) - 258 = 0-2735 0 Part (t) – -2.1- 273 _ 373_------ .-.1 .0 731---- rrrrrrrrrrrrrrrrera -.- .-.- 0:27 - - - - 0-2.68_5 - *