Homework Answers
Answer:
a).
The order of genes is -----
s------25.21 m.u.---------- w---13. 36m.u.--c
b). s w+ c+ / s+ w c
c). RF between c & w = 13.36%
d). RF between w & s = 25.21%
e). 0.45
Explanation:
|
Shorthand |
Number of progeny |
Class |
|
w s c+ |
13 |
double cross over |
|
w+ s+ c+ |
165 |
double cross over |
|
w+ s+ c |
13 |
single cross over |
|
w s+ c+ |
82 |
single cross over |
|
w+ s c+ |
436 |
single cross over |
|
w+ s c |
79 |
single cross over |
|
w s c |
162 |
Parental cross over |
|
w s+ c |
450 |
Parental cross over |
|
Total |
1400 |
Imagine the parental genotype of gametes are w+ s c+ & w s+ c
1. If single cross over (SCO) occurs between w+ & s and w & s+
Normal order= w+---------s & w-----s+
After cross over= w+------s+ & w-----s
w+------s+ recombinants are 165+ 13 = 178
w-----s recombinants are 162 + 13 = 175
Total recombinants = 353
RF = (353/1400.)*100 =25.21%
2. If single cross over (SCO) occurs between s & c+ and s+ c
Normal order= s---------c+ & s+----c
After cross over= s-----c & s+------c+
s-----c recombinants are 79+162= 241
s+------c+ recombinants are 165+82 = 247
Total recombinants = 488
RF = (488/1400)*100 = 34.86%
3. If single cross over (SCO) occurs between w+ & c+ and w & c
Normal order= w+---------c+ & w------c
After cross over= w+-----c & w------c+
w+ -----c recombinants are 13+79= 92
w------c+ recombinants are 13+82= 95
Total recombinants = 187
RF = (187/1400)*100 =13.36%
% RF = Map unit distance
Distance between the w & s = 25.21 mu
Distance between the s & c = 34.86 mu
Distance between the w & c = 13.36 mu
The order of genes is -----
s------25.21 m.u.---------- w---13. 36m.u.--c
RF between s & w = 25.21% = 0.2521
RF between w & c = 13.36% = 0.1336
Expected double cross overs = 0.2521 * 0.1336 = 0.0337
The correct parental genotype of gametes are s w+ c+ & s+ w c
Observed double cross overs are s w c+ & s+ w+ c = 13 + 13
= 26/1400 = 0.0186
Observed double cross progeny are more than the expected double cross over progeny.
Coefficent of coincidence (CC) = Obeserved dco / Expected dco
CC = 0.014/0.032 = 0.55
Interference = 1-CC = 1-0.55 = 0.45
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