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Part A In a population of rabbits, f(C) = 0.23 and 1(C) = 0.77. The alleles exhibit an incomplete dominance relationship in w
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Answer #1

According to Hardy Weinberg equilibrium,

C12 + 2C1C2 + C22 = 1 or C1 + C2 = 1

Where, C1 = f(C1) = 0.23

C2 = f(C2) = 0.77

A. Frequency of black rabbits, f(C1C1)= C12 =(0.23)² = 0.05

B. Frequency of tan rabbits, f(C1C2)= 2C1​​​​​​1C2 = 2×0.23×0.77 = 0.35

C. Frequency of white rabbits, f(C2C2)= C22 = (0.77)² = 0.59

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