The Ka value for HF is 3.5×10?4.
Part A
Calculate the change in pH when 2.0×10?2mol of NaOH is added to 0.50 L of a buffer solution that is 0.15 M in HF and 0.20 M in NaF.
Note: can you break it down in steps so i can understand how it was solved? Thanks
The Ka value for HF is 3.5×10?4. Part A Calculate the change in pH when 2.0×10?2mol of NaOH is added to 0.50 L of a b...
Determine the pH of a solution that is 1.00 L of 0.100 M HF and 0.100 M NaF after 0.50 mole of solid KOH has been added to the solution. Ka(HF) = 3.5×10-4
A.) Calculate the pH of 0.100 L of a buffer solution that is 0.29M in HF (Ka = 3.5 x 10-4 ) and 0.55M in NaF. B.) What is the pH after adding 0.004mol of HNO3 to the buffer described in Part A? C.) What is the pH after adding 0.002mol of KOH to the buffer described in Part A?
28. A 0.50 L buffer solution is 0.20 M in HF and 0.40 M in NaF. The Ka for HF is 1.5 x 10*. Show all work for full credit. (a) Calculate the pH of the solution after the addition of 0.025 moles of solid KOH. (3 pts) (b) Calculate the pH of the solution after the addition of 0.050 moles of HCI. (3 pts)
What is the pH of a 1.0 L buffer made with 0.300 mol of HF (Ka = 6.8 × 10⁻⁴) and 0.200 mol of NaF to which 0.100 mol of NaOH were added?
28. A 0.50 L buffer solution is 0.20 M in HF and 0.40 M in NaF. The Ka for HF is 1.5 x 10". Show all work for full credit. (a) Calculate the pH of the solution after the addition of 0.025 moles of solid KOH. (3 pts)
28. A 0.50 L buffer solution is 0.20 M in HF and 0.40 M in NaF. The Ka for HF is 1.5 x 10* Show all work for full credit. (a) Calculate the pH of the solution after the addition of 0.025 moles of solid KOH. (3 pts) (b) Calculate the pH of the solution after the addition of 0.050 moles of HCl. (3 pts)
help with 5 and 6 please 5. Choose the effective pH range of a HF/Naf buffer. For HF, Ka = 3.5 x 10-4 6. If a small amount of a strong acid is added to buffer made up of a weak acid, HA, and the sodium salt of its conjugate base, NaA, the pH of the buffer solution does not change appreciably because a) the Ka of HA is changed. b) the strong acid reacts with Ato give HA, which...
Calculate the pH of a buffer that is 0.040 M HF and 0.020 M LIF. The Ka for HF is 3.5 x 10-4.
Given a 1.00 L solution that is 0.60 M HF and 1.00 M KF, calculate the pH after 0.060 mol NaOH is added, and calculate the pH after 0.20 mol HCl is added to the original solution. Ka = 7.2x10-4 pH = when NaOH is added pH = when HCl is added
5) A 1 L buffer solution is 0.520 M in HF and 0.520 M in NaF. Calculate the pH of the solution after adding 0.220 moles of NaOH. Assume no volume change upon the addition of a base. Ka for HF is 3.5 X 10-4