The electron affinity of fluorine is -328 kJ mol-1. Which of the reactions shown below has a reaction energy of +328 kJ mol-1?
A) F+(g) + e- ---> F(g)
B) F(g) + e- ---> F-(g)
C) F-(g) + e- ---> F2-(g)
D) F-(g) ---> F(g)+ e-
E) F(g) ---> F+(g)+ e-
F) F+(g) ---> F2+(g)+ e-
The electron affinity of fluorine is -328 kJ mol-1. Which of the reactions shown below has a reaction energy of +328 kJ...
Sodium has an electron affinity of-52.9 kJ/mol, while the electron affinity of magnesium is +40 kJ/mol. 4. a) Which of these elements may, under extreme circumstances, be made into an anion? b) Explain why the electron affinity of magnesium is larger than that of sodium.
Energy diagrams for two reactions are shown. Energy (kJ/mol Energy (kJ/mol) Reaction progress Reaction A Reaction progress Reaction B What is the heat of reaction for Reaction A? What is the heat of reaction for Reaction B? AHA = AHxnB = mol What is the activation energy for Reaction A? What is the activation energy for Reaction B? Earn A = mol mol
Calculate the lattice energy for LiF(s) given the following: sublimation energy for Li(s) = +166 KJ/mol delta Hf for F(g) = +77 KJ/mol first ionization energy of Li(g) = +520 KJ/mol electron affinity of F(g) = -328 KJ/mol enthalpy of formation of LiF(s) = -617 KJ/mol
Energy diagrams for two reactions are shown. 1501 150 Energy (kJ/mol) Energy (kJ/mol Reaction progress Reaction progress Reaction A Reaction B What is the heat of reaction for Reaction A? What is the heat of reaction for Reaction B? ΔΗχη Α = kJ AHxB= kᎫ mol mol What is the activation energy for Reaction A? What is the activation energy for Reaction B? Earxn A = kJ Ea rxnB = mol mol
Part C The ionization energy for rubidium is 403 kJ/mol The electron affinity for iodine is-295 kJ/mol. Use these values and Hess's law to calculate the change in enthalpy for the following reaction per mole of reagent: Rb(g) +I(g)Rb+ (g) +I (8), AH=? Express your answer with the appropriate units. ► View Available Hint(s) AH per mole = Value Units Submit
Determine the lattice energy (in kJ/mol) of NaF(s), using the data provided. Energy to sublime Na(s) = 109.0 kJ/mol Electron affinity of F(g) = -328.0 kJ/mol First ionization energy of Na(g) = 495.0 kJ/mol Bond energy of F2(g) = 154.0 kJ/mol ΔHrxn for Na(s) + 1/2 F2(g) → NaF(s) = -569.0 kJ/mol
Select which process describes the following energy changes. (Ionization energy, electron affinity, bond enthalpy, or standard enthalpy of formation A. F(g) + e- => F-(g) B. F2(g) => 2F(g) C. Na(g) => Na+(g) + e- D. Na(s) + 1/2F2(g) => NaF(g)
Use bond energies, values of electron affinities, and the ionization energy of hydrogen (1312 kJ/mol) to estimate AH for the following reaction Bond Energies Electron Affinities H-F (565 kJ/mol) F() (-328 kJ/mol) H-CI (427 kJ/mol) C1(9) (-349 kJ/mol) -(295 kJ/mol) 1(9) (-295 kJ/mol) 0_H(467 kJ mol) OH(g) (-180. kJ/mol) H2O(g) + H+ (g) + OH (9) AHL b HCI(g) + H+ (g) + CI" (9) AH = kJ
The following reaction can be written as the sum of two reactions, one of which relates to ionization energy and one of which relates to electron affinity: Li(g)+F(g)→Li+(g)+F−(g) Part A What is the reaction that corresponds to the first ionization energy of lithium, Li ? Part B What is the reaction that corresponds to the electron affinity of fluorine, F ? Both A and B need to be in CHEMICAL Equation.
atomic mass 190.23 8 mol electronegativity 2.20 electron affinity 106.1 kr mol kJ ionization energy 840. mol kJ heat of fusion mol You may find additional useful data in the ALEKS Data tab. Does the following reaction absorb or release energy? 1 O release absorb Can't be decided with the data given. (1) Oshg) + 2 + Os(g) O yes Is it possible to calculate the amount of energy absorbed or released by reaction (1) using only the data above?...