Question

1. Please predict the solubility of I₂ in water, benzene, and ethanol, respectively, and explain your prediction.

Answer 1

We know that I2 is a nonpolar molecule and it will be readily soluble in non-polar solvents as "LIke dissolves like"The solubility of I2 in water:

Water is polar and I2 being nonpolar, so we expect that the I2 in slightly soluble or rather insoluble in water as it does not form any weak interactions like hydrogen bonds with water or any dipole interactions.

Benzene is a nonpolar solvent so it will enhance the solubility of I2 and will give red color because of the charge-transfer complex.

Ethanol is a polar solvent but not that much of water, So the solubility of I2 will be larger compared to water.