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I just need the last two parts of the question answered.

PM.66 Real estate developer Russell Call was working with a few contractors to make a number of improvements to one of his re

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Answer #1
Activity Normal time Crash time Normal cost Crash cost Slope Crash limit
A 3 2 $1,050 $3,200 $2,150 1
B 6 5 $2,000 $2,560 $560 1
C 3 2 $1,300 $2,600 $1,300 1
D 7 3 $2,200 $2,600 $100 4
E 6 3 $1,800 $2,400 $200 3
F 4 3 $4,200 $5,540 $1,340 1
G 4 2 $1,600 $2,050 $225 2

Slope = (Crash cost - Normal cost) / (Normal time - Crash time).

The rule of crashing is to crash the activity on the critical path which has the least slope.

Initial State Start 4 母一母 4 Project paths Duration Normal cost $14,150 Crash cost S0 A-D-G 14 $14,150 16 Total cost B-E-G C-F

Step-1: Crash E by 2 weeks 7 End Start 4 4 4 Project paths Duration $14,150 Normal cost Crash cost $400 A-D-G 14 Total cost B

Step-2: Crash G by week Start End 4 4 Project paths Duration $14,150 Normal cost A-D-G 13 Crash cost $625 13 Total cost $14,7

So,

Cost of crashing the project to 13 weeks is $625 and the total cost is $14,775 (Choose the answer that is desired, the language is twisted, i.e. whether they want the total cost or just the cost of crashing is not very clear).

Step-3: Crash G by week End Start 4 4 Project paths Duration $14,150 Normal cost Crash cost $850 A-D-G 12 $15,000 Total cost

Step-4: Crash D and E by 1 week each Start End 4 Project paths Duration $14,150 Normal cost Crash cost $1,150 $15,300 A-D-G T

So,

Cost of crashing the project to 11 weeks is $1,150 and the total cost is $15,300 (Choose the answer that is desired, the language is twisted, i.e. whether they want the total cost or just the cost of crashing is not very clear).

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