Show work please. A converging lens with a focal length of 20 cm is used to form an image on a screen that is 2.2 m beh...
A converging lens with a focal length of 40 cm is used to form an image on a screen that is 2.8 m behind the lens. At what distance in front of the lens must the object be placed?
A diverging lens of focal length –30.0 cm is placed 25.0 cm behind a converging lens of focal length 60.0 cm. A real, upright object of height 2.00 cm is placed 20.0 cm in front of the converging lens. (a) Determine the location of the final image. (Clearly state the location of the final image.) (b) Determine the size and the nature of the final image.
An object is placed 58.0 cm from a screen. Where should a converging lens of focal length 5.5 cm be placed to form a clear image on the screen? (Give your answer to at least one decimal place.) shorter distance ________ cm from the screen farther distance ________ cm from the screen Find the magnification of the lens. magnification if placed at the shorter distance ________ magnification if placed at the farther distance ________
15. (3 points) A convex lens of focal length of 20 cm is used to form an image of an object on a screen. (The setup is somewhat similar to what you used in the lab however it is not exactly the same.) The height of the object is 20 mm and the height of the image on the screen is 40 cm. (Note UNITS in the previous sentence!) How far from the lens must the screen be placed? Report...
A converging lens with a focal length of 40 cm and a diverging lens with a focal length of -68 cm are 188 cm apart. A 3.1-cm-tall object is 60 cm in front of the converging lens. Calculate the distance between image and diverging lens. Calculate the image height.
Let an object be placed 5 cm in front of a converging lens of focal length 10 cm. A second converging lens of focal length 20 cm is placed 20 cm to the right of the first lens. Find the image location and its characteristics.
A converging lens of focal length 20.0 cm is separated by 50.0 cm from a converging lens of focal length 5.00 cm. a) Find the position of the final image of an object placed 42.0 cm in front of the first lens. Solve graphically and mathematically. b) If the height of the object is 2.00 cm, what is the height of the final image? c) Is the final image real or virtual? Is it inverted or upright?
An object is placed 7.5 cm in front of a converging lens with a focal length f1 = 2.5 cm. On the other side of the lens is a concave mirror of focal length f2 = 1.5 cm. The mirror is 5.0 cm from the lens. Light from the object passes rightward through the lens, reflects from the mirror, passes leftward through the lens, and forms a final image of the object. ksid tet to What is the distance between...
20. An object is placed 100 cm in front of a converging lens of focal length 20 cm. If the height of the object is 6.0 cm, what is the height of the final image? a. 0.75 cm b. 1.5 cm c. 3.0 cmm d. 25.0 cm e. None of the above
An object located 30.0 cm in front of a lens forms an image on a screen 7.80 cm behind the lens. (a) Find the focal length of the lens. cm (b) Determine the magnification (c) Is the lens converging or diverging? diverging converging