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A 2.00 kg cube is placed on a frictionless floor a shot by compressing a spring (k 1500. N/m) 0.125 m. A. What is the velocit

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Answer #1

A.

e = due

1500 2 X 0.125 m/s

V = 3.42 m/s

B.

mu? = mgh = mgd sin e ( Conservation of energy)

“ 2g sino

3.42 2 x 9.8 x sin 30°

d = 1.19 m

C.

a = -g sino

a = -(9.8 x sin 30°) m/s

a = -4.9 m/s

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