Question

Calculate the molar mass of the unknown acid using the titration data:

Given:

Mass of acid: 0.2128g

Volume of NaOH delivered: 8.30 mL

Moles acid: 0.2074 mol

Molar mass of acid: ?

Answer 1

Ind method : and for mono preotic and :- mole of Naon x Imole of aid = moles of Imole of bare moles of Naon = 0.207 4x Imole of base Imole of and moles of Naon = 0.20764 or 0.207 Molarity of NaoH = No. of moles in solution Ilolin(Lit) 0 0 = 0. 2074 T000 molarity of NaoH = 24.99 RUSSIT Molar mass of aid = civen mans Moles of auid Given mass moles of base 1 monopuotic and 7 maut in In - Given mass mobity & Volume { :: Molanity = no d moles 0.2128 24-9 X 8.30 e TODO Molar mass = 1.02 REDMI NOTE 5 PRO MI DUAL CAMERA

Solution : Given; man of and = 0.2128 g Volume of Naon delivered - 8.30ml moles of aid = 0.2074 moles find :- Molarmass of and = ? Case I of Acid is monopustic Reaction - MX + Naon H₂O + Nax formula - No. of moles= mass (given) Molar mas Molar mars (aid) = mass given card) No. of moles (aud) = 0.21289 0.2074 moles = 1.02 g/moles Case I :- ff aid is Dipreotic Hg x + 2 Naon q Nax + 2H₂O moles of and= 0.2074 -0.1037 CHE Molormass = man given moles of and 0.2128 6 11037 = 2.05 g/moles REDMI NOTE 5 PRO MI DUAL CAMERA
this can be solved by both the method giving same result