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5. Circle the structural isomers (same formula different arrangement) below: нас Нccн, но сн Нусусн,

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Answer #1

5. There are no structural isomers given to circle.

The first compound is n-butane with formula C4H10

The second compound is 2-butene with molecular formula C4H8

The third compound is 2-methyl butane C5H12

Structural isomers are those compounds which are having the same molecular formula but different molecular arrangement.

For the given three compounds there are three different molecular formulae and there is no chance to exist structural isomers in between them.

The first given compound is a normal alkane, a simple hydrocarbon

The second given compound is a normal alkene with a double bond

The third given compound which is similar to first compound has an extra single methyl group substitution at the second carbon.

Thus as molecular formulae of any two compound do not match, there are no structural isomers in between them.

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5. Circle the structural isomers (same formula different arrangement) below: нас Нccн, но сн Нусусн,
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