Question

I don't know how to reach the answer for (b) which is  and need help with (a) and (c) as well.

A gas phase reaction proceeded by way of two parallel first order reactions as shown below: i) CH,CООН — СHa + CO2 ii Н,С-С-0 + H-0 CH,COОН In an experiment conducted at 450 °C the concentration of acetic acid was followed as а) a function of time. Describe how to use the data collected to find the rate constant for the disappearance of acetic acid. [2 marks] In an experiment conducted at 450 °C involving 5.0 mmol acetic acid, the rate constant b) for disappearance of acetic acid was found to be k= 6.35 s1 and the amount of methane at the end of the reaction to be 3.5 mmol. Based on this information find the rate constants for each of the two parallel reactions (i) and (ii) at 450 °C. [5 marks] Above 500 °C the decomposition of acetic acid proceeds nearly exclusively via reaction c) i). Based on this observation, what can be concluded in regards to which reaction is under thermodynamic and kinetic control, respectively? Explain your answer [3 marks] (b) In an experiment conducted at 450 °C involving 5.0 mmol acetic acid, the rate constant for disappearance of acetic acid was found to be k = 6.35 s and the amount of methane at the end of the reaction to be 3.5 mmol. Based on this information find the rate constants for each of the two parallel reactions (i) and (ii) at 450 °C nCH4 2.33 ki k 6.35 s1 =ki+ kii nCH2CO k 4.44 s and kji= 1.91 s

Answer 1

Please go through the explanation

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Dale d Censeoly Congrory dt Rt dt Lo Co ln Co kt n Co k = t Concentraton the use differeut CHe CODH at dota Lay -te eacton imes Cafculate R AM (b gtial wple ot Cencoon k= (,tR,) 6.35 5- end of Reati methane au@unt 3.5 to Reaction sham n tt ustas af Actic acid CAR)> 5uimDA Ascog total 3-5 3. wud acid t Acctic to tol wuoS .*. uшal used f preducig CHy acio! Acctic wm of CEC-0 S-2.S l:5ynl

nate of to7waton o metuaue Ri Cengioory ent late of forhation o H-@-o kiCaugesoy t Ngt4 itak

tintiaf 3.5 3.5 . Ct2-t) V tr- toj yoArat . eud 4 3. reny -t) (t2-ti) 3. 2.33 Rc 6.35 R, + k, > 6. 31- - R2 R, -/ 6.35-R2 Re 2.33 6.3- 1.9o7 - 4.443| g-1 Ri = 6-35