Question

What are the concentration of this following solutions

1. 5mL of 10ppm Fe+2 diluted in a 100mL volumetric flask

2. 10mL of 10ppm Fe+2 diluted in a 100mL volumetric flask

3. 20mL of 10ppm Fe+2 diluted in a 100mL volumetric flask

4. 25mL of 10ppm Fe+2 diluted in a 100mL volumetric flask

Answer 1

To solve given problem we can use dilution formula.

We have dilution formula, C _stock$\times$ V _stock = C _dilute$\times$ V _dilute.

Where, C _stock is concentration of stock solution,  V _stock is a volume of stock solution, C _dilute is concentration fo dilute solution and V _dilute is volume of dilute solution.

1) Given

C _stock = 10 ppm,

V _stock = 5 ml

C _dilute = ?

V _dilute. = 100 ml

Placing given values in above formula , we get 10 ppm $\times$ 5 ml = C _dilute$\times$ 100 ml

Therefore, C _dilute = 10 ppm $\times$ 5 ml / 100 ml = 0.5 ppm

ANSWER : Concentration of diluted Fe ²⁺ solution = 0.5 ppm

2)  Given

C _stock = 10 ppm,

V _stock =10 ml

C _dilute = ?

V _dilute. = 100 ml

Placing given values in above formula , we get 10 ppm $\times$ 10 ml = C _dilute$\times$ 100 ml

Therefore, C _dilute = 10 ppm $\times$ 10 ml / 100 ml = 1.0 ppm

ANSWER : Concentration of diluted Fe ²⁺ solution = 1.0 ppm

3)

Given

C _stock = 10 ppm,

V _stock =20 ml

C _dilute = ?

V _dilute. = 100 ml

Placing given values in above formula , we get 10 ppm $\times$ 20 ml = C _dilute$\times$ 100 ml

Therefore, C _dilute = 10 ppm $\times$ 20 ml / 100 ml = 2.0 ppm

ANSWER : Concentration of diluted Fe ²⁺ solution = 2.0 ppm

4)

Given

C _stock = 10 ppm,

V _stock =25 ml

C _dilute = ?

V _dilute. = 100 ml

Placing given values in above formula , we get 10 ppm $\times$ 25 ml = C _dilute$\times$ 100 ml

Therefore, C _dilute = 10 ppm $\times$ 25 ml / 100 ml = 2.5 ppm

ANSWER : Concentration of diluted Fe ²⁺ solution = 2.5 ppm