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Please review the background knowledge posted on iCollege. Answer the following questions. 1. 25.0mL of 0.20M Propanic acid (
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Answer #1

CH₂ CH₂COOH of NaoH - CH₃ en Conna & HO moles of CH₃ CH loof = 25 xon = 0.005 moles omladoled NaOH = CH₂ WH 200 tit H₂ CH₂COOclassmate when some Naol added - CH, CH, CooH + Nasl Core Che coorva + Hp 0.005 0.005 0 cm o o 0.005 [cts CH₂ wit CH₃ CH, Loo

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