Question

HELP ME PLEASE!!!

Interested in knowing the prices of hamburgers in the city, a group of descriptive statistics were asked, at what price do they buy hamburgers without combo and without being from a commercial chain? Below are the values that reflect the price 50 40 50 35 60 75 45 65 65 60 45 30 50 65 30 45 85 80 50 65 45 55 55 30 40 70 25 55 45 10

Answer 1

Answer: Mean (M) = 50.667 standard deviation (o)= 16.620. For ramele srecn) = 20 Peter Sample standard devgatson our - 16.620 20 - 3.0743829666 ~ 3.034 1.034 r = Now, the probability that the aruage of sample of 20 food stands of mou than 8608 P(7 860= IP(F260) =t-P/T-4 60 - 50.667) T 1.074 ) -1 P(Z23.08) Flom standard nolmal table = - 0,99896 = 0.00104 [PC8>9001-Q 00104

IP For sample size (n)-100 cocoa pample standard deviation M Co = 16.620 1.662 rn - TO 7 = 1.666 Now, the perbability that the areage of sample of 100 food Hande is more than 860.8 P(x>60) = I-PEEL GO) - 1-PCX-4 < 60-50.667 | 1.662 El-PlZL 56135284657) -|- Plze 5.62) Fon pe 1.62 From Pralue calculator from 2-valle is = |- (20.0000) BNO. 999999 - Ov 2999 :P(6760)= 0,9999] now at 820

as the probability of fonding an average price of 8 20 was at leather 257. That mean, P ( X 220J= 25%. I-P ( X €21) 25%. PLX220) = 0.75 d 75% P/XM 220.50.667 75 from e-valle 16.620 calentator for 0.75 probability z value is a. 67449 20-50.667 602 - 067449 16.620 vn - 20.667 = n 20-50.667 = 0.67449 x 16.620 - 30.667 = 11.2100234 vn in = -11. 2100212 - 0 26 JT 4 02511 in = (-0. 16559028284867 0. 1336196971 ~ 0.1 foodstande required.

The pobability of finding an aruage price of X80 was at most 750. It can de written as P(X480) = 757 P ( XS 80) = 0.75 Ar 4 e 50-50.667 I - 16.620 -0.75 Form & valen calculation sou or Probability revalle is ñ 0.67449 80-80.667 = 0.67449 16.620 ra 29.333 = 0.6674498 16,620 Vn n = 0.67449 x 16.620 0.382164 245 29.13 n= (0.387164245 & 0.1460495102 & 0.5 0.15 food stands required