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from burde Mass of aluminum foil Mass of 50 ml beaker + alum Mass of 50...
how do i find theoretical yield of alum and the percent yield of alum Mass of...
how do i find theoretical yield of alum and the percent yield
of alum
Mass of aluminum foil Mass of 50 mL beaker + alum Mass of 50 mL beaker 1.019 40.99 30.35 10.59 88*C-1030 732-96c Mass of alum Melting point range of pure alum Melting point range of your alum Theoretical yield of alum Percent yield of alum Supporting calculations: The net reaction is: 2Al(s) + 2KOH + 22H2O + 4H2SO4 2KAI(SO4)2-12H2O + 3H2 Theoretical yield of alum Percent...
2Al(s)+2KOH(aq)+4H2SO4+22H2O(l)→2KAl(SO4)2⦁12H2O(s)+3H2(g) What is the limiting reactant, theoretical and percent yield of this equation? 1.03 grams of...
2Al(s)+2KOH(aq)+4H2SO4+22H2O(l)→2KAl(SO4)2⦁12H2O(s)+3H2(g) What is the limiting reactant, theoretical and percent yield of this equation? 1.03 grams of Al foil 35.10 grams of KOH 15 grams of Sulfuric acid 20 grams of water the mass of the product is 24.88 grams
Synthesis of Alum (Potassium Aluminum Sulfate) from Aluminum Aluminum cans can be recycled to make potassium...
Synthesis of Alum (Potassium Aluminum Sulfate) from Aluminum Aluminum cans can be recycled to make potassium aluminum sulfate dodecahydrate, KAK(SO)12H20, which is abbreviated to "alum". The 12 waters are part of the overall formula. Alum can be used to make dyes, printing fabrics, making paper, adhesives, pickling of food and vets use it to induce a dog to throw up. x 1 rxn 2 run 3 The following are the four reactions that lead to alum: Al(s) + 2 KOH...
Post La DUI LUI U UUDLUNS What is the biggest factor that causes vields of alum...
Post La DUI LUI U UUDLUNS What is the biggest factor that causes vields of alum in this experiment to be low? using too much Hasoy whold cause the yield to be in 2. A student reacted 1.01 g of Al with 25.0 mL of 2.00 M KOH according to the following reaction: 2Al(s) + 2KOH(aq) +6H2O(0) ► 2KAI(OH)4 + 3H2(g) a. How many moles of KOH were required to react with all of the aluminum? b. How many moles...
Mass of 150 mL beaker 83.60g Mass of CuSO4 5 H2O 2.15g Mass of Al foil...
Mass of 150 mL beaker 83.60g Mass of CuSO4 5 H2O 2.15g Mass of Al foil pieces 0.25356g Mass of beaker + solid copper 84.18g Mass of solid copper 0.58g Balanced equation: 2 Al + 3 CuSO4 ---> 3 Cu + Al2(SO4)3 0.00861 mol of CuSO45H2O used 9.73974 x 10-3 mol of Al used 1. Find the the theoretical yield in grams of copper and also state the limiting reactant in this experiment
can I please get help solving number 4 Weignto comes9423 weight of beaker & alum 972.2313...
can I please get help solving number 4
Weignto comes9423 weight of beaker & alum 972.2313 Caleulations Dare 3-30-20 section - 2. Weight of alum crystals collect 2 ALO2 og beint of bener 164309 1.789g weight of beakertal 0 865. alig 3. Equations representing the synthesis Write below equations 1, 2, and 3 given in the text (+2KOH lag) HOH₂O 2kg + 2Al(OH)4 + 3H2198 32nrag)+ ZAILOH) ülaa)+4H250ulag) 2Kt Loa) +241 lagt 3 tlac) +A1312029100) #210-> AS042 4. Mole relationships...
ass (g) of Aluminum foil used 0.6551 Mass (g) of filter paper 1.0896 Edit Mass (g)...
ass (g) of Aluminum foil used 0.6551 Mass (g) of filter paper 1.0896 Edit Mass (g) of filter paper and alum Thy 22.7693 Edit Try Ente Tole Thy two Try 2 0.02428 Moles (moles) of aluminum used Thy Thy 2 Adria infor Theoretical yield of slum Actual yield of alum Percent yield (5) of slum NG Why wasn't your actual yield 100% If your Experimental Errors What happened during the experiment that may have alread your res was greater, how...
Перо Name _Date Section 1. mass of aluminum 16.2058 2. mass of alum possible (theoretical yield)...
Перо Name _Date Section 1. mass of aluminum 16.2058 2. mass of alum possible (theoretical yield) 3. mass of alum produced (actual yield) 4. percent yield Show calculations by number: 10:52 Exit If you removed the solvent from 50.07 mL of a 1.403 M copper(II) sulfate solution, how many grams of copper(II) sulfate would you have? Question 2 3 pts The solubility of copper(II) bromide in water is 55.7 g/100 mL of water at 20 C. If you have a...
Mass of empty 150 mL beaker 83.60g Mass of CuSO45H2O 2.15 Mass of Al 0.25356g Mass...
Mass of empty 150 mL beaker 83.60g Mass of CuSO45H2O 2.15 Mass of Al 0.25356g Mass of beaker + solid copper 84.10g Mass of solid copper 0.50g 2 Al + 3 CuSO4 ---> 3 Cu + Al2(SO4)3 8.61x10-3 mol of CuSO45H2O used 9.3974x10-3 mol of Al used Theoretical yield in grams of copper is 0.547g 1. Find the percent yield from this reaction.
1. Mass of 50 ml beaker labelled “5 g NaCl” 30.2846 g 2. Mass of 50...
1. Mass of 50 ml beaker labelled “5 g NaCl” 30.2846 g 2. Mass of 50 ml beaker + ~5.00 g NaCl 35.0111 g 3. Volume of distilled water 20.0 mL 4. Mass of 50 mL beaker + ~5.00 g NaCl + water 54.9981 g 5. Volume of “5 g NaCl” solution 22.2 mL 1. Exact mass of NaCl in beaker labelled “5 g NaC1” 2. Exact mass of solution in beaker labelled “5 g NaCl” g 3. Density of...
how do i find theoretical yield of alum and the percent yield
of alum
Mass of aluminum foil Mass of 50 mL beaker + alum Mass of 50 mL beaker 1.019 40.99 30.35 10.59 88*C-1030 732-96c Mass of alum Melting point range of pure alum Melting point range of your alum Theoretical yield of alum Percent yield of alum Supporting calculations: The net reaction is: 2Al(s) + 2KOH + 22H2O + 4H2SO4 2KAI(SO4)2-12H2O + 3H2 Theoretical yield of alum Percent...
Synthesis of Alum (Potassium Aluminum Sulfate) from Aluminum Aluminum cans can be recycled to make potassium aluminum sulfate dodecahydrate, KAK(SO)12H20, which is abbreviated to "alum". The 12 waters are part of the overall formula. Alum can be used to make dyes, printing fabrics, making paper, adhesives, pickling of food and vets use it to induce a dog to throw up. x 1 rxn 2 run 3 The following are the four reactions that lead to alum: Al(s) + 2 KOH...
Post La DUI LUI U UUDLUNS What is the biggest factor that causes vields of alum in this experiment to be low? using too much Hasoy whold cause the yield to be in 2. A student reacted 1.01 g of Al with 25.0 mL of 2.00 M KOH according to the following reaction: 2Al(s) + 2KOH(aq) +6H2O(0) ► 2KAI(OH)4 + 3H2(g) a. How many moles of KOH were required to react with all of the aluminum? b. How many moles...
can I please get help solving number 4
Weignto comes9423 weight of beaker & alum 972.2313 Caleulations Dare 3-30-20 section - 2. Weight of alum crystals collect 2 ALO2 og beint of bener 164309 1.789g weight of beakertal 0 865. alig 3. Equations representing the synthesis Write below equations 1, 2, and 3 given in the text (+2KOH lag) HOH₂O 2kg + 2Al(OH)4 + 3H2198 32nrag)+ ZAILOH) ülaa)+4H250ulag) 2Kt Loa) +241 lagt 3 tlac) +A1312029100) #210-> AS042 4. Mole relationships...
ass (g) of Aluminum foil used 0.6551 Mass (g) of filter paper 1.0896 Edit Mass (g) of filter paper and alum Thy 22.7693 Edit Try Ente Tole Thy two Try 2 0.02428 Moles (moles) of aluminum used Thy Thy 2 Adria infor Theoretical yield of slum Actual yield of alum Percent yield (5) of slum NG Why wasn't your actual yield 100% If your Experimental Errors What happened during the experiment that may have alread your res was greater, how...
Перо Name _Date Section 1. mass of aluminum 16.2058 2. mass of alum possible (theoretical yield) 3. mass of alum produced (actual yield) 4. percent yield Show calculations by number: 10:52 Exit If you removed the solvent from 50.07 mL of a 1.403 M copper(II) sulfate solution, how many grams of copper(II) sulfate would you have? Question 2 3 pts The solubility of copper(II) bromide in water is 55.7 g/100 mL of water at 20 C. If you have a...
1. Mass of 50 ml beaker labelled “5 g NaCl” 30.2846 g 2. Mass of 50 ml beaker + ~5.00 g NaCl 35.0111 g 3. Volume of distilled water 20.0 mL 4. Mass of 50 mL beaker + ~5.00 g NaCl + water 54.9981 g 5. Volume of “5 g NaCl” solution 22.2 mL 1. Exact mass of NaCl in beaker labelled “5 g NaC1” 2. Exact mass of solution in beaker labelled “5 g NaCl” g 3. Density of...
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