Given :-
Sample mean ( ) = 2.0
Sample standard deviation (s) = 4.7
Sample size (n) = 61
Degree of freedom (df) =n-1 =61-1 =60
Confidence level (c) = 98%
Then critical value is tc= 2.39
Now, we have to find confidence interval for mean
Therefore,
= ( )
= ( )
= ( 2.0 - 1.44 , 2.0 + 1.44 )
= ( 0.56 , 3.44 )
Therefore the 98% confidence interval about mean () is 0.56 to 3.44 .
df to.10 0.025 t0.01 to.0ns df Values of ta 3.078 6.314 2.706 31.821 63.657 1886 2.920...
df o.10 0.05 e.025 to.01 0.005 df Values of ta 3.078 6.314 12.706 31.821 63.657 1.886 2.920 4.303 6.965 9.925 1.638 2.353 3.182 4.54 5.84 1.533 2.132 2.776 3.747 4.604 0 1476 2.015 2.57 3.365 4.032 1.440 1.943 2.447 3.143 3.707 1.415 1895 2.365 2.998 3.499 1.397 1860 2.306 2.896 3.355 1.383 1833 2.262 2.82 3.250 1.372 1.812 .228 2.764 3.169 1.363 796 .20 2.718 3.106 1.356 1.782 2.179 2.68 3.055 1.350 177 2.160 2.650 3.012 1.345 1.76 2.145 2.624...
Using a table of critical t-values of the t distribution, find the range of values for the P-value for testing a claim about the mean body temperature of healthy adults for a left-tailed test with n=12 and test statistic t= -2.475 What is the range of values for the P-value? A. 0.01 <P-value< 0.025 B. 0.025<P-value<0.05 C. P-value<0.005 D. 0.005 <P-value<0.01 x t-table t distribution: Critical t values 0.005 0.01 Area in One Tail 0.025 0.05 0.10 Degrees of Freedom...
3. Using the t-distribution table posted on Moodle, find the df & critical t-values given N & the confidence level: N 30, 90% confidence level b. N 17, 90% confidence level c. N 23, 95% confidence level d. N 42, 99% confidence level e. N o 1,95% confidence level a. t-distribution Table TABLE D Thet distribution* Confidence interval percents (two-tailed) 80% 90% 95% 98% 99% 99.9% a level for two-tailed test 20 .10 .05 02 01 .001 a level for...
Find the critical value(s) and rejection region(s) for the indicated t test level of significance α and sample size n Left-tailed test, α: 0.005, n 7 Click the icon to view the t-distribution table. The critical value(s) isare (Round to the nearest thousandth as needed. Use a comma to separate answers as needed ) Determine the rejection region(s) Select the correct choice below and filt in the answer boxies) within your choice Round to the nearest thousandth as needed) OB...
T Distribution Table The U.S. Dairy Industry wants to estimate the mean yearly milk consumption. A sample of 25 people reveals the mean yearly consumption to be 82 gallons with a standard deviation of 24 gallons. Assume that the population distribution is normal. (Use Distribution Table.) a-1. What is the value of the population mean? 82 24 Unknown a-2. What is the best estimate of this value? Estimate population mean c. For a 90% confidence interval, what is the value...
t-distribution Table -Distribution Area in Right Tail 0.025 0.02 df 0.25 0.20 0.15 0.10 0.05 0.01 0.005 0.0025 0.001 0.0005 3 6 1.000 1.3761.963 0.816 1.061 1.386 0.765 0.978 1.250 0.741 0.941 1.190 0.727 0.9201.156 0.718 0.906 1.134 0.7110.8961.119 0.706 0.889 1.108 0.703 0.883 1.100 0.700 0.879 1.093 0.697 0.876 1.088 0.695 0.873 1.083 0.694 0.870 1.079 0.692 0.868 1.076 0.691 0.866 1.074 0.690 0.865 1.071 0.689 0.863 1.069 0.688 0.862 1.067 0.688 0.861 1.066 3.078 1.886 1.638 1.533 1.476...
(a) Does the evidence suggest that community college transfer students take longer to attain a bachelor's degree? Use an α = 0.05 level of significance. Perform a hypothesis test. Determine the null and alternative hypotheses. (b) Determine the test statistic (t = ?) and the P-value (P = ?). Round to two decimal places as needed. (c) Construct a 90% confidence interval for (μcommunity college − μno transfer) to approximate the mean additional time it takes to complete a bachelor's...
9.2.17 Question Help A simple random sample of size nis drawn from a population that is normally distributed. The sample mean, X, is found to be 106, and the sample standard deviations, is found to be 10. (a) Construct a 96% confidence interval about if the sample size, n, is 17 (b) Construct a 96% confidence interval about if the sample size, n, is 22 (c) Construct a 98% confidence interval about if the sample size, n, is 17 id...
I ONLY NEED HELP WITH PART OF PART "B" I've figured out the test statistic is -1.73 and the degrees of freedom are 5. However, I'm having a hard time finding the P value via the chart (which I'm required to learn how to do).I think the chart immediately bellow this is the one used to find the p-value. However, I know at least one (or more) of the charts bellow is what's used. Please let me know which chart...
I ONLY NEED HELP WITH PART OF PART "B" I've figured out the test statistic is -1.73 and the degrees of freedom are 5. However, I'm having a hard time finding the P value via the chart (which I'm required to learn how to do).I think the chart immediately bellow this is the one used to find the p-value. However, I know at least one (or more) of the charts bellow is what's used. Please let me know which chart...