Draw the structure of the organic product of each reaction in the following two-step synthesis.
The concept used to solve the given problem is the knowledge of the nucleophilic addition reaction on the carbonyl carbon.
The carbonyl carbon has the electrophilic carbon which is deficient in electrons and is fulfilled by the nucleophilic attack which results in the nucleophilic addition product.
The nucleophile attacks the antibonding orbital of the carbonyl carbon result in the breakage of the bond between C and O.
In the given reactant the proton attacks the lone pair of oxygen which further proceed with the intramolecular attack of as a nucleophile on the carbonyl results in the formation of cyclic imine.
The mechanism of this reaction is given below:
When the cyclic imine reacts with reducing agent such as undergoes reduction and the imine group converts into the cyclic secondary amine which is commonly known as piperdine.
The reaction of reduction of cyclic imine is as follows:
Ans:The structure of the organic product of each reaction for the two-step synthesis are as follows:
Draw the structure of the organic product of each reaction in the following two-step synthesis. Draw...
Draw the structures of the organic products in each reaction of the following two-step synthesis.
Draw the structures of the organic products in each reaction of the following two-step synthesis. (Hint: The nucleophilic amine attacks the electrophilic carbonyl carbon, and the resulting intermediate undergoes a proton shift and dehydration. Recall what is eliminated in a dehydration process. The second step is a reduction reaction; the reducing agent is NaBH3CN (or H2, metal catalyst). The aromatic ring is unaffected by these reagents. Look at the product of the first reaction and consider what can be easily...
Draw the structures of the organic products in each reaction of the following two-step synthesis. (Hint: The nucleophilic amine attacks the electrophilic carbonyl carbon, and the resulting intermediate undergoes a proton shift and dehydration. Recall what is eliminated in a dehydration process. The second step is a reduction reaction; the reducing agent is NaBH3CN (or H2, metal catalyst). The aromatic ring is unaffected by these reagents. Look at the product of the first reaction and consider what can be easily...
Draw the structure of the major product of each step in the following three-step synthesis. As a start, one benzene ring is drawn for you in each product.
Draw the structure of the product of each step in the following three- step synthesis. Show all formal charges.
Draw the structure of the product of each step in the following three-step synthesis. If a nitro group is in the structure, use the functional group tool to put it in, do not draw it out (i.e. put in NO2). Although the first step produces a mixture of isomers, the para isomer is isolated as the sole product of interest and used in the second step. Give only the major product for the second and third steps. HNO Brz Br2...
Draw the structure of the product of each step in the following three-step synthesis. Show the formal charges, if applicable. As a start, the benzene ring is drawn for you in each product.Although the first step produces a mixture of isomers, the para isomer is isolated as the sole product of interest and used in the second step. Give only the major product for the second and third steps.
Draw the structure of the product of each step in the following three-step synthesis. Show all formal charges.
Draw the structure(s) of the major organic product(s) of the following reaction. Draw the structure(s) of the major organic product(s) of the following reaction. If no reaction occurs, draw the organic starting material. Draw enolates in their carbanion form. Include counter e.g., Na^+, I^-, in your submission, but draw them in their own separate sketcher. For multi-step processes, draw the product(s) of the last step.
"Draw the structure of the product of each step in the following three-step synthesis. Show all formal charges." I'm so confused right now. I got the first compound right but the last two are wrong. In red, it says that "Although an organometallic compound forms from reaction with Mg, it is not the final product of the 2nd overall step. Further reaction - with CO2 and then acid - gives the product that you need to draw." HNO 1.Mg 2.Co...