1.A 1.5 meter long pendulum has a period of how many seconds? 2. If you initially...
There should be two answers.
2. If you initially displace the pendulum above by 8 degrees and release it from rest, where will the pendulum be and what will its velocity be 5.4 seconds later? nline
7. How long must a simple pendulum string be to have a period of 2 seconds on mars where the acceleration due to gravity at the surface is 0.376g.
5. A pendulum has a period of 0.75 seconds and an undamped amplitude of 8.5. A damping force can be turned on which has a time constant of 4.5 s. A. What is the frequency of the oscillation without damping? B. Once the damping is turned on, how long will it take for the frequency to decrease to 35% of the undamped amplitude? C. How many oscillations will the pendulum make in the time determined in part B?
5. A pendulum has a period of 0.75 seconds and an undamped amplitude of 8.5'. A damping force can be turned on which has a time constant of 4.5 s. A. What is the frequency of the oscillation without damping? B. Once the damping is turned on, how long will it take for the frequency to decrease to 35% of the undamped amplitude? C. How many oscillations will the pendulum make in the time determined in part B?
How long should a 9.8 N pendulum be in order to have a period of 2 seconds when on the moon where it only weighs 1.65 N
QUESTION 7 A 2 kg pendulum swings 4 times in 10 seconds. It has a period of QUESTION 8 A 2 kg pendulum swings 4 times in 10 seconds. It has a frequency of cycles per second QUESTION 9 Hz. If a pendulum completes 25 cycles in a minute, its frequency is
1. How much is the period of 1=1.00 m long pendulum on the Moon (g = 1.600 m/s2) 4.97 sec. 2. On a planet X pendulum of the length 0.500 m makes 50.0 oscillations in 1.00 min. Find the acceleration of gravity on the planet X. g = 13.7 m/s2. 3. Find the period of small oscillations of a meter stick suspended by its end near Earth surface (assume g=9.800 m/s2). Notice that this is not a simple pendulum but...
(1 point) Suppose a pendulum with length L (meters) has angle 0 (radians) from the vertical. It can be shown that 0 as a function of time satisfies the differential equation: d20 + -sin 0 = 0 dt2 L where g = 9.8 m/sec/sec is the acceleration due to gravity. For small values of 0 we can use the approximation sin(0) ~ 0, and with that substitution, the differential equation becomes linear A. Determine the equation of motion of a...
Previous Problem List Next 11 point) Suppose a pendulum with length Limeters) has angle iradians) from the vertical. It can be shown that as a function of time satisfies the differential equation: do sin = 0 de? Z . and with that substitution, the differential where g = 9.8 m/sec/sec is the acceleration due to gravity. For small values of we can use the approximation sin(0) - equation becomes Inear A. Determine the equation of motion of a pendulum with...
2) You are designing a pendulum clock to have a period of 0.75s. How long should the pendulum be? (0.14m) How much should the pendulum bob (the mass at the end) weigh? (Does not matter. T is independent of mass of the pendulum.)