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A student performed a titration of an unknown amino acid that had two ionizable groups. The student determined the pKa values
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Answer #1

Isoelectronic point = 1/2 * (pKa1 + pKa2)

= 1/2 * (4.79 + 10.20)

= 1/2 * 14.99

= 7.50

Answer: 7.50

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