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22. Imagine that a new population of humans is established on a new planet from ten randomly selected people in your genetics

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22. C. The Founder Effect

Note: When a population of few members establishes a new community solely by mating within themselves, it decreases the genetic variability. This phenomena is known as Founder Effect. One very popular example is the Amish Community.

23. B. Trinucleotide Repeat Disease

Note: Trinucleotide Repeat Disease is caused when the number of trinuleotide repeats increases beyond their threshold in a gene. This kind of mutation makes the gene unstable. One such common example is expansion of CAG repeats, which codes for glutamine and hence gives rise to Polyglutamine disorder, such as seen in Hungtinton's disorder. So this kind of genetic change happens in nuclear gene.

Maternal effect is a phenomena, when some trait of the child is governed by mothers genotype. This is basically happened because of the maternal deposition of RNA and not nuclear gene.

24. A. Large and Randomly Mating.

Note: Hardy Weinberg's Principle states that, the genetic variation in a population will remain constant from one generation to other if no external variability disrupts the equilibrium.

This principle is applicable if the population is infinitely large and individuals are mating randomly.  

25. C. 0.40

Solution: According to Hardy Weinberg principle: p2 + 2pq + q2 = 1, where p is the frequency of dominant allele A and q is the frequency of recessive allele a.

Hence, the frequency of dwarfism allele, q2 = 16% = 16/100

q = 4/10 = 0.4

26. B. 70

Solution: Homozygous (AA) individuals contain two copies of allele A and Heterozygous (Aa) individuals contain one copy of allele A. Hence The total number of allele A present in the population, according to the information given, is (20 x 2) + 30 = 70.

27. E. The frequency of allele A is 0.6;
The frequency of allele a is 0.4

Solution: According to Hardy Weinberg principle: p2 + 2pq + q2 = 1, where p is the frequency of dominant allele A and q is the frequency of recessive allele a.

So the frequency of allele A is = freq(AA) + (1/2) freq(Aa) = 0.5 + 0.2/2 = 0.6.

And the frequency of allele a = 1 - freq(A) = 1 - 0.6 = 0.4.

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