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1. A charge of 0.080C moves horizontally in a field of 0.1 T that is oriented at an angle of 45° with respect to charge direc
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Answer #1

f = q (u x B) = qu B sino = 0.080 xu xo.axsin as ISN lu= 2651.65 mis lay.l a f= q (u x B) a fa quB sine (7)= . 5 Xox 0.8 x 3x1²xsino to = 0.058 33 m sino = 0.05833 To = 3.344 as

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