Question

Using the precedence table given, draw an activity-on-node diagram network and determine the ESD EFD. LSDLFD, and Te for each

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Answer #1

ESD = Earliest Start Date

EFD = Earlies Finish Date

LSD = Latest Start Date

LFD = Latest Finish Date

Critical path is the path of activities having maximum duration

TE ESD EFD DURA LED TION

ESD = LSD of previous activity (Note; If there is more than one predecessors, take the highest value of LSD)

:LSD = ESD + Duration

LFD = EFD of succeeding activity   (Note; If there is more than one predecessors, take the lowest value of EFD)

EFD = LFD - Duration

TF = (LFD - EFD) or (EFD - ESD)

TE23 TF=0 TF-0 | A3 TF=0 c 11 TF=3 11 E 12 14 1 16 TF=0 H 21 8 11 17 4 21 TF=3 12 G 14 |15| 2 | 17 | TE 9 12 3 15

Sample calculation

Activity E

ESD = LSD of previous activity  

= 11

:LSD = ESD + Duration

= 11 + 1 = 12

LFD = EFD of succeeding activity

= 15

EFD = LFD - Duration

= 15 - 1 = 14

TF = (LFD - EFD) or (EFD - ESD)

= (15 - 12) or (14 - 11)

= 3

TE=3 11 E 12 14|1|15

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Critical Path is the path of activities having Total float equal to 0

From the above network diagram, we can conclude that A-C-F-H is the critical path

Therefore option C is the correct answer

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