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9. Given the following information in the table, construct an activity on the node diagram. Label the critical path as well a
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Ci 3 2 0 3IH 81.89 3 36 10 21 2. 귀-2.2 3

The critical path is marked by the double line as it is the shortest duration for the activities to complete.

Early start the soonest the project will start, so for C it is only after A and B both are done. C will start after 3 days and Early finish is Early start + duration, I.e 3+3 =6

The box is in this format Early start, then activity, then early finish

On the second line it is late start, duration and late finish, in the 3rd image the box is there.

Late start is late finish - duration , so for H it is 14 which we take from early finish, 14-3 =11. F has 2 choices we always take lesser of the two late starts in late finish like for B. It has 3 of C late start and 7 of D late start. It took 3.

Total float is Early start- Late start, similarly Early finish- Late finish. It is on the top of the box. For A 0-0 and 3-3 =0

Free float is the slack time it is for eg for A: Early start of C- Early start of A - duration. 3-0-3 =0. free float is on the bottom of the box

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9. Given the following information in the table, construct an activity on the node diagram. Label the critical path as well as the early and late start/finish times and the slack for each activit...
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