Question

4 Work and Energy A Work S Scenario tart the right ho r Diction, wie Dinged by a rotace Poe wou. There were on the cartes fachon oft ghed bless 2 4 6 8 10 12 14 16 18 20 Data Analysis Claim That will have the ima l energy of 48 is depenent is changed by 12 m. Collect evidence about the physical meaning of the area under the line on the graph that can be used to support the above White an equation including units for the area between the force Evidence. The area under the Inect the force dapa t This graph is equal to is allow done on the object Reasoning: Fill in the Bandsad the filowing statement The calm makes because the done on the cart is also equal to the change of the art Explain uw graph bewwel determine the final al of the cele 12 m. PARTO 4A Work Using Representations On the one to the matchchart of the othe wit afatio d o m - m -12m. MD: A no del Angela "Oh, these of a woty grappresents the et Sa, since the scelerisco 4 min the world be with a spomis Do you with Angela isplacement (1) Explain PARTE flerta l of the wody of the car as a functional displacement

Answer 1

Part A.

The area under the line of the force vs displacement time graph is equal to

4 N x 12 m = 48 J

This area is also known as the work done on the object.

This claim make sense because the work done on the cart is equal to the change in kinetic energy of the cart.

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Part B.

Using the graph we find the work done on the object for x = 12. The work done on the object is equal to the change in the kinetic energy of the cart.

W = KE_f - KE_i

Now using the expression of the kinetic energy for the final and initial position, we find the final speed V_f.

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Part C. The acceleration of the cart = force /mass= 4 N/ 1kg = 4 m/s² .

The figure below shows the graph of the acceleration.

Dipement ? (7) m ayo

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Part D. Yes, I agree with Angela.

The slope of velocity vs time graph is acceleration. Since the acceleration is constant. So the graph of velocity vs time

is a straight line with slope = acceleration = 4 m/s² .

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